c++ - (1U << X)有什么作用？

我找到了这段代码:

enum
{
  IsDynamic = (1U << 0),  // ...
  IsSharable = (1U << 1), // ...
  IsStrong = (1U << 2)    // ...
};

(1U << X)有什么作用？

最佳答案

它设置位掩码:

1U << 0 = 1
1U << 1 = 2
1U << 2 = 4
etc...

发生的情况是1U(无符号值1)向左移动x位。

您发布的代码等效于:

enum
{
      IsDynamic = 1U,  // binary: 00000000000000000000000000000001
      IsSharable = 2U, // binary: 00000000000000000000000000000010
      IsStrong = 4U    // binary: 00000000000000000000000000000100
}