我正在使用此代码共享分数的屏幕截图:
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
sharingIntent.setType("image/png");
Uri image = Uri.parse(Environment.getExternalStorageDirectory().toString() + "/sharescore.png");
try {
// create bitmap screen capture
View v1 = v.getRootView();
v1.setDrawingCacheEnabled(true);
Bitmap bitmap = Bitmap.createBitmap(v1.getDrawingCache());
v1.setDrawingCacheEnabled(false);
File imageFile = new File(image.getPath());
FileOutputStream outputStream = new FileOutputStream(imageFile);
int quality = 100;
bitmap.compress(Bitmap.CompressFormat.JPEG, quality, outputStream);
outputStream.flush();
outputStream.close();
} catch (Throwable e) {
// Several error may come out with file handling or OOM
e.printStackTrace();
}
sharingIntent.putExtra(Intent.EXTRA_STREAM, image);
startActivity(Intent.createChooser(sharingIntent, getString(R.string.share_via)));
它适用于whatsapp-twitter等,但当我使用“imgae/jpeg”类型时,它也不适用于snapchat和instagram。这会导致错误“选定的图像无法打开”。我怎样才能让Snapchat和Instagram发挥作用。
最佳答案
他们的问题是,我把截图保存到SD卡上,但是Snapchat没有从外部存储器读取文件的权限。我必须使用只能由我的应用程序访问的应用程序目录,并且必须使用我自己的文件提供程序(com.test.fileprovider)更改权限,以便Snapchat可以访问它。代码如下:
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
sharingIntent.setType("image/jpg");
sharingIntent.setFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
File newFile = new File(getContext().getCacheDir(), "share_score.jpg");
Log.d(getClass().getSimpleName(), newFile.getAbsolutePath());
Uri image = FileProvider.getUriForFile(getContext(), "com.test.fileprovider", newFile);
try {
// create bitmap screen capture
View v1 = v.getRootView();
v1.setDrawingCacheEnabled(true);
Bitmap bitmap = Bitmap.createBitmap(v1.getDrawingCache());
v1.setDrawingCacheEnabled(false);
FileOutputStream outputStream = new FileOutputStream(newFile);
int quality = 100;
bitmap.compress(Bitmap.CompressFormat.JPEG, quality, outputStream);
outputStream.flush();
outputStream.close();
} catch (Throwable e) {
// Several error may come out with file handling or OOM
e.printStackTrace();
}
sharingIntent.putExtra(Intent.EXTRA_STREAM, image);
startActivity(Intent.createChooser(sharingIntent, getString(R.string.share_via)));