我已经在我的Android应用程序中集成了Snapchat的Creative Kit。处理后,我从服务器收到了字节数组形式的图像,将其保存到磁盘,然后将文件发送到Snapchat的Creative Kit,如下所示。

 private fun downloadImage(
    fileName: String,
    imageByteArray: ByteArray?): Uri? {
    val state = Environment.getExternalStorageState()

    if (Environment.MEDIA_MOUNTED == state) {
        val downloadDir = File(
            Environment.getExternalStorageDirectory(), context?.getString(R.string.app_name)
        )

        if (!downloadDir.isDirectory) {
            downloadDir.mkdirs()
        }

        val file = File(downloadDir, fileName)
        var ostream: FileOutputStream? = null
        try {
            ostream = FileOutputStream(file)
            ostream.write(imageByteArray)
            ostream.flush()
            ostream.close()
            }
        } catch (e: IOException) {
            e.printStackTrace()
        }

    val snapCreativeKitApi = SnapCreative.getApi(context!!)
    val snapMediaFactory = SnapCreative.getMediaFactory(context!!)
    lateinit var snapPhotoFile: SnapPhotoFile
    try {
        snapPhotoFile = snapMediaFactory.getSnapPhotoFromFile(file)
    } catch (e: SnapMediaSizeException) {
        return
    }
    val snapPhotoContent = SnapPhotoContent(snapPhotoFile)
    snapCreativeKitApi.send(snapPhotoContent)
    }
}

我还在 list 文件中添加了provider,如下所示:
  <provider
        android:name="androidx.core.content.FileProvider"
        android:authorities="${applicationId}.provider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths_app" />
    </provider>

provider_paths_app.xml中,我通过引用this答案尝试了所有可能的路径,但没有一个起作用。
<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
<external-path
    name="My App Name"
    path="." />
</paths>

通过上面的路径,我得到下面的错误。
Couldn't find meta-data for provider with authority my.package.name.fileprovider

我所要做的就是将此图像发送到Snapchat,但我无法弄清楚自己在做什么错。任何帮助将不胜感激。

最佳答案

首先在标签下的 list 中写入以下标签

 <provider
            android:name="androidx.core.content.FileProvider"
            android:authorities="${applicationId}.provider"
            android:exported="false"
            android:grantUriPermissions="true">
            <meta-data
                android:name="android.support.FILE_PROVIDER_PATHS"
                android:resource="@xml/provider_paths" />
        </provider>

然后在res中创建一个xml文件夹并创建一个文件名:Provide + paths.xml
然后复制粘贴代码:
<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <external-path
        name="external_files"
        path="." />
</paths>

现在大多数开发人员在程序中错误地在程序中创建File,那么我们将使用:
FileProvider.getUriForFile(Objects.requireNonNull(getApplicationContext()),
                    BuildConfig.APPLICATION_ID + ".provider", file);

希望这对您有用!

08-18 00:57