java - 随机分配游戏板的障碍

我想使用随机数生成器在游戏板上放置障碍物。 5％的棋盘会有一个被定义为“ *”的底坑，但除非玩家落在该位置，否则星号不会显示；木板的10％将被阻塞的斑点表示为“ X”；剩下的85％将是显示为“”的开放空间。游戏板是一个10x10的数组，左上角的字母“ P”作为玩家的起点，右下角的字母“ T”作为结束符（宝物）。到目前为止，我已经掌握了这一点，并且我一直在观看视频教程以及阅读以尝试将所有内容放在一起，但仍然存在问题：

import java.util.Scanner;
import java.util.Random;

public class Adventure {

    public static void main(String[] args) {
        char grid[][]= new char[10][10];
        Scanner move = new Scanner(System.in);
        System.out.println("Here is the current game board:");
        System.out.println("-------------------------------");

        for(int i=0; i<grid.length; i++) {
            for(int j=0; j<grid.length; j++) {
                grid[i][j]='.';
                grid[0][0]='P';
                grid[9][9]='T';
                System.out.print(grid[i][j]);
            }
        Random obstacle = new Random();
        int obstacleNum;
        for(int k=1; k<=100; k++) {
            obstacleNum = 1+obstacle.nextInt(100);

        }
            System.out.println("");
        }
        System.out.printf("Enter your move (U/D/L/R)>");
    }
}

不知道在“ obstacleNum = 1 + obstacle.nextInt（100）;”之后应该去哪里？

最佳答案

至于实际的交互性，这是一个概述：

x = 0; //coordinates of player, location of P
y = 0;

要隐藏凹坑，在打印之前，请粘贴if语句：

if(grid[i][j]=='*') {
    System.out.println("."); //looks like ordinary land
} else {
    System.out.println(grid[i][j]);
}

现在在收到输入时运行此命令（伪）

//following if for moving left
if(grid[y][x+1] isn't out of bounds and right key is pressed and grid[y][x+1]!='X') {
    grid[y][x] = '.'; //removes current position
    x++; //change location
}
//following if for moving right
if(grid[y][x-1] isn't out of bounds and left key is pressed and grid[y][x-1]!='X') {
    grid[y][x] = '.'; //removes current position
    x--; //change location
}
//following if for moving down
if(grid[y+1][x] isn't out of bounds and down key is pressed and grid[y+1][x]!='X') {
    grid[y][x] = '.'; //removes current position
    y++; //change location
}
//following if for moving up
if(grid[y-1][x] isn't out of bounds and up key is pressed and grid[y-1][x]!='X') {
    grid[y][x] = '.'; //removes current position
    y--; //change location
}
if(grid[y][x] == '*') { //when trapped in a pit
    System.out.println("You fell in a pit. Game over.");
} else {
    grid[y][x] = 'P'; //update grid
}

关于java - 随机分配游戏板的障碍，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/9187352/