嗨,我正在尝试访问从Lua发送到C的嵌套表。
该表是:
arg =
{
MagicNumber = {MagicNumber, 0},
ProdNum = {ProdNum, 1},
LetterR = {LetterR, 0xc},
Revision = {Revision, 0xd},
Space1 = {Space1, 0xe},
MnfctrCode = {MnfctrCode, 0xf},
Hyphen1 = {Hyphen1, 0x12},
ZeroCode = {ZeroCode, 0x13},
Hyphen2 = {Hyphen2, 0x15},
MnfctrMnth = {MnfctrMnth, 0x16},
MnfctrYear = {MnfctrYear, 0x18},
SerialNum = {SerialNum, 0x1a},
Space2 = {Space2, 0x1e},
ChkSum = {ChkSum, 0x1f},
}
里面的表都是整数值,表中的键是字符串。我的代码段如下所示:
lua_pushnil(L);
while(lua_next(L, -2) != 0)
{
field = lua_tostring(L, -2);
printf("\n %d field = %s", i, field);
wrData[i-1] = lua_tonumber(L,-1);
printf("\n data = 0x%x", wrData[i-1]);
lua_pop(L, -1);
i++;
}
我错过了什么吗,因为我得到的值是
0x0
。 最佳答案
更改此函数以满足您的需要,并使用堆栈顶部的表进行调用。
void luaAccess(lua_State * L)// call this function with the table on the top of the stack
{
lua_pushnil(L);
while(lua_next(L, -2))
{
switch(lua_type(L, -2))
{
case LUA_TSTRING:
//deal with the outer table index here
break;
//...
// deal with aditional index types here
}
switch(lua_type(L, -1))
{
case LUA_TTABLE:
lua_pushnil(L);
while (lua_next)
{
switch(lua_type(L, -2))
{
case LUA_TNUMBER:
// deal with the inner table index here
break;
//...
// deal with aditional index types here
}
switch(lua_type(L, -1))
{
case LUA_TSTRING:
//deal with strings
break;
case LUA_TNUMBER
//deal with numbers
break;
}
lua_pop(L, 1);
}
//...
// deal with aditional index types here
break
}
}
lua_pop(L, 1);
}