我想为numpy.random选择一个随机种子并将其保存到变量中。我可以使用numpy.random.seed(seed=None设置种子)，但是如何让numpy选择一个随机种子并告诉您它是什么呢？
默认情况下，Number似乎在Linux上使用/dev/urandom。
最佳答案
RandomState基础的MT19937 PRNG的完整状态不能包含在单个(正常大小，例如32位或64位)整数中。它的状态为624个32位整数的数组。实际上，使用整数进行播种会运行更小，更简单的PRNG，以生成这624个字。这是人类将PRNG的状态手动设置为可以一致复制的状态的一种便捷方法。但是大多数声明PRNG进入的状态不能还原为方便的32位整数。初始化程序PRNG不能以这种方式“向后”工作。相反，RandomState的整个状态都包含在该624个条目的数组中。您可以使用 get_state() 和 set_state() 方法获取并设置该数组。
>>> import numpy as np
>>> prng = np.random.RandomState()
>>> state = prng.get_state()
>>> state
('MT19937',
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624,
0,
0.0)
>>> prng.random_sample()
0.20598058788141316
>>> prng.random_sample()
0.6864005375257146
>>> prng.random_sample()
0.08407651896523582
>>> prng.set_state(state)
>>> prng.random_sample()
0.20598058788141316
>>> prng.random_sample()
0.6864005375257146
您也可以腌制
RandomState对象。我们使用get_state()数据实现了此功能，因此它将可靠地重现PRNG的状态。根据确切的操作(不说)，这通常是最方便的操作，而不是手动操作get_state()和set_state()。>>> import cPickle
>>> pickled = cPickle.dumps(prng)
>>> prng.random_sample()
0.08407651896523582
>>> prng.random_sample()
0.3501860271954601
>>> prng2 = cPickle.loads(pickled)
>>> prng2.random_sample()
0.08407651896523582
>>> prng2.random_sample()
0.3501860271954601
关于python - 选择随机种子并保存，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/20911147/