我正在尝试读取文件,然后按字符输出文件。我希望用户输入一个数字,该数字将是要显示的行数。
如果没有以下行,我的代码将显示整个文本文件。
如果(y == lineCount)中断;
当计数的换行符数量等于用户输入的数量时,此行应该打破循环。
我可以计算newLine字符的数量并显示出来,但是当我尝试达到一定数量的newLines后中断循环时,代码将在1个字符后中断
#include <stdio.h>
int main ( int argc, char *argv[] )
{
FILE *file = fopen( argv[1], "r" );
int lineCount, x, y;
printf("enter a number of lines of lines to be displayed\n");
scanf("&d", &y);
while ( ( x = fgetc( file )) != EOF ) //read characters
{
printf( "%c", x ); //print character
if (x == '\n') //check for newline character
lineCount++;
if (y == lineCount) //check for newLine character
break; //??? y = lineCount after 1 character???
}
printf( "%d lines in the text file\n", lineCount ); //testing the newline characters was being read
fclose( file );
}
最佳答案
您要用scanf(“%d”,&y)而不是scanf(“&d”,&y)。