我有两个具有列(id,Rname,电子邮件)的表“餐厅”和具有列(id,item_name,item_price,Rname)的“ food_items”。现在,我要开发一个页面,其中将显示所有餐厅及其各自的食品。如下所示:
Restaurant Name1:
item 1
item 2
item 3
我为此做了很多尝试,但是我没有得到想要的确切信息。
我写了一个sql查询,显示的是餐厅名称,然后是餐厅名称,但这没有给我确切的信息。
<?php
$sql1 = "SELECT DISTINCT mi.item_name, mi.item_price, mi.veg_nonveg, rs.Rname FROM menu_items AS mi LEFT JOIN restaurants AS rs ON mi.Rname=rs.Rname";
$result1 = mysqli_query($conn,$sql1);
if(mysqli_num_rows($result1)){
foreach ($result1 as $rows) {
echo "<br>" . $rows['item_name'] . " " . $rows['item_price'] . " " .
$rows['Rname'];
}
}
实际结果是:
item_name, item_price , Restaurant name (Rname)
chicken curry 105 abc
veg fried rice 101 abc
Veg Momos 50 abc
veg fried rice 100 xyz
预期结果 :
ABC:
Chicken curry 105
veg fried rice 101
veg momos 50
xyz:
veg fried rice 100
最佳答案
您可以通过sql
来实现相同的目的,而不是通过php
来实现:
例如,如果您从数据库收到的数据是这样的:
$data = [
['Rname' => 'Restaurant 1', 'item_name' => 'foo', 'item_price' => '354631', 'veg_nonveg' => 'veg'],
['Rname' => 'Restaurant 1', 'item_name' => 'bar', 'item_price' => '234631', 'veg_nonveg' => 'veg'],
['Rname' => 'Restaurant 2', 'item_name' => 'foo', 'item_price' => '334234', 'veg_nonveg' => 'non-veg'],
['Rname' => 'Restaurant 2', 'item_name' => 'bar', 'item_price' => '45353', 'veg_nonveg' => 'non-veg'],
];
您可以执行以下操作:
// To print restaurant name only once in a group we need to store the
// already printed restaurant somewhere.
$restaurant = ''; // declared this variable to store current restaurant.
foreach ($data as $row) {
// checking if current restaurant is already printed.
if ($restaurant != $row['Rname']) {
//if current restaurant is not printed then we will print new one and store new restaurant.
$restaurant = $row['Rname'];
echo $row['Rname'] . "\r\n";
}
// here we are doing the regular stuff.
echo $row['item_name']. ' ' .$row['item_price']. ' ' . $row['veg_nonveg']. "\r\n";
}
在此处检查工作示例:working example
编辑:
另一种方式:
例如,我们有两个表:
作者:
+----+------+-------------+
| id | name | description |
+----+------+-------------+
| 1 | abc | som |
| 2 | def | description |
| 3 | ghi | here |
+----+------+-------------+
书:
+----+------+------+-----------+
| id | name | year | author_id |
+----+------+------+-----------+
| 1 | ijk | 1990 | 1 |
| 2 | lmn | 1991 | 1 |
| 3 | opq | 1995 | 2 |
| 4 | rst | 1996 | 2 |
| 5 | uvw | 2000 | 3 |
| 6 | xyz | 2001 | 3 |
+----+------+------+-----------+
提取数据的最简单方法是运行两个
sql
查询:首先获取作者:
SELECT * FROM author;
然后通过作者的ID来获取他们的书:
SELECT * FROM book where author_id IN (1,2,3);
现在要分组打印作者的书,我们可以按
author_id
打印书:foreach ($authors as $author) {
echo $author['name'] . "\r\n";
foreach ($books as $book) {
if ($book['id'] == $author['author_id']) {
echo $book['name']. ' ' .$book['year']. "\r\n";
}
}
}
尽管我们在这里运行两个查询,但这是管理数据的更简洁的方法。实现分页时,这也使事情变得容易。