我创建自定义ID时,im目前面临着executeScalar的问题。错误是


  用户代码未处理InvalidOperationException。
  
  Message =连接必须有效且打开。


下面是我的代码:

Dim str As String = "select isnull(max(idcr_record),0)+1 from cr_record where Emplid = '" & Session("Emplid") & "'"
Dim com As New MySqlCommand()
'this line was the error
'
Dim count As Integer = Convert.ToInt32(com.ExecuteScalar())

If count = 1 Then
    'insert if no record found
    '
    Dim cc As New MySqlCommand("insert into cr_record values (" & count & "," & Session("Emplid") & ")")
    cc.ExecuteNonQuery()
Else
    'update becoz record already exist
    '
    Dim upd As String = "update cr_record set idcr_record = " & count & " where Emplid = " & Session("Emplid") & " "
    Dim cc As New MySqlCommand(upd)
    cc.ExecuteNonQuery()
End If

Dim length As Integer = 0
Dim val As String = Convert.ToString(count)
length = val.Length
If length = 1 Then
    val = "CR " + "00000" & Convert.ToString(count)
End If
If length = 2 Then
    val = "CR " + "0000" & Convert.ToString(count)
End If
If length = 3 Then
    val = "CR " + "000" & Convert.ToString(count)
End If
If length = 4 Then
    val = "CR " + "00" & Convert.ToString(count)
End If
If length = 5 Then
    val = "CR " + "0" & Convert.ToString(count)
End If
cr_id = "" & val

最佳答案

至少,在执行命令之前,您需要将SQL命令字符串和SqlConnection对象传递给SqlCommand对象:

Dim str As String = "select isnull(max(idcr_record),0)+1 from cr_record where Emplid = '" & Session("Emplid") & "'"
Dim conn As New MySqlConnection
conn.ConnectionString = "....."

'pass your SQL command string and MySqlConnection object to MySqlCommand
'
Dim com As New MySqlCommand(str, conn)

conn.Open()
Dim count As Integer = Convert.ToInt32(com.ExecuteScalar())

关于mysql - 创建自定义ID时,ExecuteScalar错误,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/22800179/

10-09 16:02