在最后一天,我在这段代码上遇到了一些问题。在这里我想用.txt文件上传几个十六进制值,如果前五个数字之和等于最后一个数字,则代码正确无误,然后方法main必须检查其余方法是否成功。但是我不知道该怎么办,所以我需要您的帮助...
#include <iostream>
#include <fstream>
#define FILECODE "file.txt"
#define N_CODE 6
using namespace std;
ifstream file;
void uploadCode(bool& exist, unsigned int longCode, unsigned int code[]);
bool IsValidCode(unsigned int code[]);
void main() {
unsigned int code[N_CODE];
bool exist;
unsigned int longCode=N_CODE;
IsValidCode(code);
if(IsValidCode(code)==true){
uploadCode(exist,longCode,code); //here I have the problem because I don't know how to call the method
cout << "SUCCESS" << endl;
}
else
cout << "FAIL" << endl;
}
void uploadCode(bool& exist, unsigned int longCode, unsigned int code[]) {
int i;
file.open(FILECODE);
if(file){
exist=true;
for(int i=0;i<longCode;i++){
file >> hex >> code[i];
cout << "Number " << i << ": "<< code[i] << endl;
}
cout << "EXIST" << endl;
}
else
cout << "NO EXIST" << endl;
exist=false;
file.close();
}
bool IsValidCode(unsigned int code[]) {
int i;
int sum=0;
for(int i=0; i<N_CODE-1; i++)
sum+=code[i];
cout << "Sum first five numbers: " << sum << endl;
if(sum==code[6])
return true;
else
return false;
return sum;
}
最佳答案
这是满足您需求的最小修改版本。当然,应该对输入处理的返回值(即-file >> hex >> code[i];
)进行更好的检查,以查看这些输入是否真正成功。
bool uploadCode(unsigned int longCode, unsigned int code[])
{
bool ret;
file.open(FILECODE); // TODO: no need for a global here; just use a locally constructed ifstream
if (file.good())
{
ret = true;
for(int i = 0; i < longCode; ++i)
{
file >> hex >> code[i];
cout << "Number " << i << ": "<< code[i] << endl;
}
cout << "EXIST" << endl;
}
else
{
ret = false;
cout << "NO EXIST" << endl;
}
file.close();
return ret;
}
int main()
{
unsigned int code[N_CODE];
if (!uploadCode(N_CODE, code))
{
cout << "File failure!" << endl;
return 1;
}
if (!IsValidCode(code))
{
cout << "Code failure!" << endl;
return 2;
}
cout << "SUCCESS" << endl;
return 0;
}