似乎Evernote的搜索语法不允许使用多个笔记本,但我仍想获取“笔记本1”或“笔记本2”中所有包含“ somesearch”的笔记。
我可以在一个笔记本中进行一次搜索:
var token = 'xxxxXXX';
const Evernote = require('evernote');
const nFilter = new Evernote.NoteStore.NoteFilter({
words: 'somesearch notebook:"notebook 1"',
ascending: false
});
const rSpec = {};
rSpec.includeTitle = true;
var client = new Evernote.Client({token: token, sandbox: false});
var noteStore = client.getNoteStore();
noteStore.findNotesMetadata(nFilter, 0, 50, rSpec).then(function(notesMetadataList) {
console.log("Found " + notesMetadataList.notes.length + " notes.");
console.log();
console.log("Here are their titles: ");
var titles = [];
for (var i =0;i<notesMetadataList.notes.length;i++) {
titles[i]=notesMetadataList.notes[i].title;
console.log(titles[i]);
}
}).catch(function(err){
console.log('Error:',err);
});
但是我不知道如何在“ notebook 2”上进行第二次搜索,并将其标题附加到变量
titles
...顺便说一句,我在node.js编程上还很新...问候,
最佳答案
免责声明:未经测试
简短的答案是,您需要遍历笔记本,然后对结果进行汇总,然后再进行报告。我编辑了您的代码,并留下了一些指针注释。
// always put your imports first
const Evernote = require('evernote');
// default to const
const token = 'xxxxXXX';
const client = new Evernote.Client({token: token, sandbox: false});
const noteStore = client.getNoteStore();
// async await makes things cleaner
async function showTitles (noteBooks) {
const queries = [];
const rSpec = { includeTitle: true };
// the of form of the for loop avoids i++
for (const noteBook of noteBooks) {
const nFilter = new Evernote.NoteStore.NoteFilter({
words: `somesearch notebook:"${noteBook}"`,
ascending: false
});
queries.push(noteStore.findNotesMetadata(nFilter, 0, 50, rSpec))
}
// run in parallel
const results = await Promise.all(queries);
let found = 0;
let titles = [];
for (const result of results) {
found += result.notes.length;
titles = titles.concat(results.notes.map(n => n.title));
}
console.log(`Found ${found} notes.
Here are their titles:
${titles.join('\n')}`);
}
showTitles(['notebook 1', 'notebook 2']).catch(function(err){
console.log('Error:',err);
});
关于javascript - evernote api搜索+ nodejs:在两个笔记本中获取搜索结果,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/49615753/