我有以下情形:有1张桌子和书籍,两张桌子(HD / IT)的销售订单和采购订单事务通过销售订单ID连接。
表结构如下:
CREATE TABLE `books` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`isbn` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`it_id` int(11) NOT NULL,
`kind` tinyint(4) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `books` (`id`, `isbn`, `it_id`, `kind`) VALUES
(1, '12345', 1, 1),
(2, '12345', 1, 2),
(3, '67890', 2, 1),
(4, '1111111', 2, 2);
CREATE TABLE `porders_hd` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`dt` date NOT NULL,
`so_id` int(11) DEFAULT NULL,
`customer` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `porders_hd` (`id`, `dt`, `so_id`, `customer`) VALUES
(1, '2017-07-02', 1, 1),
(2, '2017-08-03', NULL, 3);
CREATE TABLE `porders_it` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`hd_id` int(11) NOT NULL,
`isbn` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`dscr` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`qty` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `porders_it` (`id`, `hd_id`, `isbn`, `dscr`, `qty`) VALUES
(1, 1, '12345', 'Book 1', 1),
(2, 2, '1111111', 'Book 2', 1);
CREATE TABLE `sorders_hd` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`dt` date NOT NULL,
`customer` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `sorders_hd` (`id`, `dt`, `customer`) VALUES
(1, '2017-07-01', 1),
(2, '2017-08-01', 2);
CREATE TABLE `sorders_it` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`hd_id` int(11) NOT NULL,
`isbn` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`dscr` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`qty` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `sorders_it` (`id`, `hd_id`, `isbn`, `dscr`, `qty`) VALUES
(1, 1, '12345', 'Book 1', 1),
(2, 2, '67890', 'Book 2', 1);
总而言之,有:
* 1个销售订单(#1)也存在于采购订单(#1)中
* 1个销售订单(#2)仍在处理中
* 1个未创建销售订单的采购订单(#2)
我希望能够获取每本书的isbn的所有销售和采购订单,并且所连接的SO和PO必须位于同一行。输出必须类似于以下内容:
so_id so_date po_id po_date isbn dscr
NULL NULL 2 2017-08-03 1111111 Book 2
1 2017-07-01 1 2017-07-02 12345 Book 1
2 2017-08-01 NULL NULL 67890 Book 3
我试图使用以下查询来抢占行:
SELECT
GROUP_CONCAT(so_id) so_id,
GROUP_CONCAT(so_date) so_date,
GROUP_CONCAT(po_id) po_id,
GROUP_CONCAT(po_date) po_date,
isbn,
dscr
FROM (
SELECT
hd.so_id so_id,
NULL so_date,
hd.id po_id,
hd.dt po_date,
bk.isbn,
it.dscr
FROM porders_hd hd,
porders_it it,
books bk
WHERE it.hd_id = hd.id
AND bk.isbn = it.isbn
AND kind = 2
UNION
SELECT
hd.id so_id,
hd.dt so_date,
NULL po_id,
NULL po_date,
bk.isbn,
it.dscr
FROM sorders_hd hd,
sorders_it it,
books bk
WHERE it.hd_id = hd.id
AND bk.isbn = it.isbn
AND kind = 1
) as table1
GROUP BY isbn, so_id, po_id
但是由于缺少信息,我得到以下结果:
so_id so_date po_id po_date isbn dscr
NULL NULL 2 2017-08-03 1111111 Book 2
1 2017-07-01 NULL NULL 12345 Book 1
1 NULL 1 2017-07-02 12345 Book 1
2 2017-08-01 NULL NULL 67890 Book 3
有什么想法可以实现吗?
最佳答案
我认为这是您所追求的,但是我无法从您的代码中找出kind
的作用。但是,这是一个查询,对于每本书,获取关联的po订单项,找到相应的so订单项,并连接标题行,以便日期可用。请注意,我的假设是销售订单不能与相应的采购订单一起存在。
SELECT books.isbn, books.descr, sorders_hd.id, sorders_hd.dt, porders_hd.id, porders_hd.dt
FROM book
join porders_it on porders_it.isbn = books.isbn
join porders_hd on porders_hd.id = porders_it.hd_id
left outer join sorders_it on sorders_it.hd_id=porders_hd.so_id and sorders_it.isbn = porders_it.isbn
left outer join sorders_hd on sorders_hd.id = sorders_it.hd_it
您可以对表进行规范化,以便不必重复描述,也可以在其他表中使用book.id而不是isbn。
关于mysql - mysql GROUP BY想法,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45529789/