scala - 使用Jackson的Scala枚举的JSON序列化

在本文之后https://github.com/FasterXML/jackson-module-scala/wiki/Enumerations

枚举声明为

object UserStatus extends Enumeration {
  type UserStatus = Value
  val Active, Paused = Value
}

class UserStatusType extends TypeReference[UserStatus.type]
case class UserStatusHolder(@JsonScalaEnumeration(classOf[UserStatusType]) enum:   UserStatus.UserStatus)

DTO被声明为

class UserInfo(val emailAddress: String, val  userStatus:UserStatusHolder) {

}

并且序列化代码是

val mapper = new ObjectMapper()
mapper.registerModule(DefaultScalaModule)

def serialize(value: Any): String = {
    import java.io.StringWriter
    val writer = new StringWriter()
    mapper.writeValue(writer, value)
    writer.toString
}

产生的JSON序列化为

{
    "emailAddress":"[email protected]",
    "userStatus":{"enum":"Active"}
}

是否有可能获得以下表格？

{
    "emailAddress":"[email protected]",
    "userStatus":"Active"
}

最佳答案

你有没有尝试过:

case class UserInfo(
   emailAddress: String,
   @JsonScalaEnumeration(classOf[UserStatusType]) userStatus:   UserStatus.UserStatus
)

jackson 维基的例子有点误导。您不需要holder类。它只是具有该元素的事物的一个示例。您需要的是注释