具体来说,我正在尝试在Java上运行下一行:
convert /home/mohamed.hegab/Desktop/1263392123111.jpg -gamma .45455 -resize 400x400 -gamma 2.2 -quality 92 /home/mohamed.hegab/Desktop/small.jpg
在bash命令行上运行得很好
但是当我使用进程生成器在Java上运行它时,它给了我奇怪的结果。
public static void resizeImage(String srcPath, String destPath,String size) {
ProcessBuilder pb = new ProcessBuilder("convert", srcPath , " -gamma", ".45455",
" -resize",size, " -gamma ", "2.2", " -quality",
"92" , destPath);
pb.redirectErrorStream(true);
InputStreamReader isr = null;
BufferedReader br = null;
try {
Process p = pb.start();
p.waitFor();
isr = new InputStreamReader(p.getInputStream());
br = new BufferedReader(isr);
String line = null;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
} catch (Exception e) {
LOG.error("Exception while trying to convert text to image", e);
} finally {
try {
if(isr != null) {
isr.close();
}
if(br != null) {
br.close();
}
} catch (IOException e) {
LOG.error("Could not close stream", e);
}
}
}
system.out中出现的行很奇怪,很奇怪,它说
转换:无法打开图像
-gamma': No such file or directory @ blob.c/OpenBlob/2439.convert: unable to open image
.45455':没有这样的文件或目录@ blob.c / OpenBlob / 2439。转换:无法打开图像
-resize': No such file or directory @ blob.c/OpenBlob/2439.convert: unable to open image
400x400':无此类文件或目录@ blob.c / OpenBlob / 2439。转换:无法打开图像
-gamma ': No such file or directory @ blob.c/OpenBlob/2439.convert: unable to open image
2.2':没有此类文件或目录@ blob.c / OpenBlob / 2439。转换:无法打开图像
-quality': No such file or directory @ blob.c/OpenBlob/2439.convert: unable to open image
92':没有这样的文件或目录@ blob.c / OpenBlob / 2439。但是图像仅以960 * 960的尺寸显示,我不知道它来自哪里。
所以任何人都可以在这方面帮助我:)
最佳答案
在-
之前避免空格,shell命令只能识别以-
开头的选项。