java - 如何在JPA查询上传递参数？

我有两个实体，例如SmsOut和SmsIn。两个实体之间的关系包含OneToMany，其中smsIn.id是主键，smsOut.sms_in_id是外键。

现在我想在查询中传递诸如smsIn.mobileNumber，smsIn.smsText等的参数

SELECT so FROM SmsOut so order by id desc

以下是我的数据库图：



已编辑

以下是我的代码：

String sql = "SELECT so FROM SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc";
    Query query = em.createQuery(sql);
    query.setParameter("mobileNumber", mobileNumber);
    query.setParameter("smsText", smsText);
    query.setParameter("shortCode", shortCode);
    query.setParameter("smsOutDate", startDate);
    query.setParameter("smsOutDate", endDate);
    smsOutList = query.getResultList();

和例外是：

SEVERE: line 1:188: expecting "and", found '='
java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: expecting "and", found '=' near line 1, column 188 [SELECT so FROM     com.f1soft.SMSC.entities.SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc]
at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:624)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:96)

请帮我。
谢谢

最佳答案

您尚未解释SmsIn和SmsOut之间的JPA关系，所以我假设SmsOut具有getSmsIn()且在id字段上具有关系。

拥有EntityManager em时，可以调用em.createQuery（类似于SQL prepare），然后调用setParameter：

TypedQuery<SmsOut> q = em.createQuery("SELECT so FROM SmsOut so WHERE so.smsIn.mobileNumber = :number ORDER BY id DESC");
q.setParameter("number", "12345678");
List<SmsOut> results = q.getResultList();

有关指定参数的不同方法，请参见the Javadoc for Query。