python - 基本运行周期不起作用

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我还是python的新手，并且已经开始使用pygame。我正在制作无尽的亚军游戏，但是我的运行周期遇到了问题。这是我的代码：

import pygame
import sys
from pygame.locals import *
pygame.init()
clock = pygame.time.Clock()
clock2 = pygame.time.get_ticks()
screen = pygame.display.set_mode((640, 575))
bgx = 0
bgx2 = -800
scroll = 10
pose = 1
background = pygame.image.load("images/background2.png").convert_alpha();
player = pygame.image.load("images/character1.png").convert_alpha();
screen.blit(background, (0, 0))
def draw_screen(x):
screen.blit(background, (x, 0))
def draw_screen2(x2):
screen.blit(background, (x2, 0))
def draw_player(pose):
    if pose == 1:
        player = pygame.image.load("images/character1.png").convert_alpha();
        screen.blit(player, (0, 0))
    elif pose == 2:
        player = pygame.image.load("images/character2.png").convert_alpha();
        screen.blit(player, (0, 0))
    elif pose == 3:
        player = pygame.image.load("images/character3.png").convert_alpha();
        screen.blit(player, (0, 0))
    elif pose == 4:
        player = pygame.image.load("images/character2.png").convert_alpha();
        screen.blit(player, (0, 0))
def set_poses(pose):
    if pose == 1:
        pose = 2
    if pose == 2:
        pose = 3
    if pose == 3:
        pose = 4
    if pose == 4:
        pose = 1

while True: #Loop
    clock2 = pygame.time.get_ticks()
    #Quitting Function
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
            quit()
    clock.tick(50)
    #Screen Scrolling
    if bgx != 800:
        bgx += scroll
    else:
        bgx = 0
    if bgx2 != 0:
        bgx2 += scroll
    else:
        bgx2 = -800
    #Drawing Items
    draw_screen2(bgx2)
    draw_screen(bgx)
    draw_player(pose)
    if clock2%6 == 0:
        set_poses(pose)
    pygame.display.update()

因此屏幕在滚动，并且出现了我的角色，但他在它运行的部分停留在第一个位置（我想是帧）。set_poses(pose)我试图让它在设置姿势之前也打印一些东西，但是确实如此。它没有设定姿势。我尝试用它打印姿势，结果表明姿势没有改变。所以，是的，我找到了问题，但我终生无法找到解决方案。

最佳答案

而不是尝试通过引用传递-这是您在做什么，请尝试如下操作：

def set_pose(pose):
    if pose >= 4:
        return 1
    else:
        return pose + 1

然后，当您尝试在其他地方更新pose变量时：

pose = set_pose(pose)

您是否同意可以随意调用函数的参数？例如，set_pose可能看起来像这样，并做完全相同的事情：

def set_pose(foo):
    if foo >= 4:
        return 1
    else:
        return foo + 1

换句话说，仅仅因为在函数内部被称为pose并不意味着它将在函数外部引用姿势。

关于python - 基本运行周期不起作用，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/38232059/