opencv - 如何将8位OpenCV IplImage *转换为32位IplImage *？

我需要将8位IplImage转换为32位IplImage。使用网络上的文档，我尝试了以下操作:

// general code
img2 = cvCreateImage(cvSize(img->width, img->height), 32, 3);
int height    = img->height;
int width     = img->width;
int channels  = img->nChannels;
int step1     = img->widthStep;
int step2     = img2->widthStep;
int depth1    = img->depth;
int depth2    = img2->depth;
uchar *data1   = (uchar *)img->imageData;
uchar *data2   = (uchar *)img2->imageData;

for(h=0;h<height;h++) for(w=0;w<width;w++) for(c=0;c<channels;c++) {
   // attempt code...
}

// attempt one
// result: white image, two red spots which appear in the original image too.
// this is the closest result, what's going wrong?!
// see: http://files.dazjorz.com/cache/conversion.png
((float*)data2+h*step2+w*channels+c)[0] = data1[h*step1+w*channels+c];

// attempt two
// when I change float to unsigned long in both previous examples, I get a black screen.

// attempt three
// result: seemingly random data to the top of the screen.
data2[h*step2+w*channels*3+c] = data1[h*step1+w*channels+c];
data2[h*step2+w*channels*3+c+1] = 0x00;
data2[h*step2+w*channels*3+c+2] = 0x00;

// and then some other things. Nothing did what I wanted. I couldn't get an output
// image which looked the same as the input image.

如您所见，我真的不知道我在做什么。我很想找出答案，但是如果我能正确完成，我会更喜欢它。
感谢您的帮助!

最佳答案

也许link可以帮助您？

编辑响应OP的第二次编辑和注释

你有没有尝试过
float value = 0.5
代替
float value = 0x0000001;
我认为 float 颜色值的范围从0.0到1.0，其中1.0是白色。

关于opencv - 如何将8位OpenCV IplImage *转换为32位IplImage *？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/394488/