mysql - SQL选择顶部查询

大家好，我有以下查询：

   SELECT TOP(1) CommitmentLog.CommitAmt
FROM   leveldetails
       INNER JOIN CommitmentLog
               ON leveldetails.App_ID = CommitmentLog.app_id
                  AND leveldetails.Intro_ID = '999'
                  AND leveldetails.Side = 'right'
                  AND CommitmentLog.flag != '1'
                  AND CommitmentLog.CommitNo NOT IN (SELECT commit_no
                                                     FROM   binary_bal
                                                     WHERE  Intro_ID = '999'
                                                            AND Side = 'right'
                                                            AND llevel BETWEEN 1 AND 100000)

第一行CommitAmt值：1500
第二行CommitAmt值：500
如果我选择CommitmentLog.CommitAmt的前1个总和，则返回值为2000而不是1500
如果我选择CommitmentLog.CommitAmt的前2个总和，则返回正确的返回值2000


  如果我选择前1，则求和（CommitmentLog.CommitAmt）
  它应该返回1500，
  如果我选择前2，则
  sum（CommitmentLog.CommitAmt）它应该返回1500 + 500 = 2000

最佳答案

您想对结果集的前N个求和？尝试这个

SELECT SUM(t1.CommitAmt) from (SELECT TOP(1) CommitmentLog.CommitAmt
                                  FROM   leveldetails
                                    INNER JOIN CommitmentLog
                                      ON leveldetails.App_ID = CommitmentLog.app_id
                                      AND leveldetails.Intro_ID = '999'
                                      AND leveldetails.Side = 'right'
                                      AND CommitmentLog.flag != '1'
                                      AND CommitmentLog.CommitNo NOT IN (SELECT commit_no
                                                     FROM   binary_bal
                                                     WHERE  Intro_ID = '999'
                                                            AND Side = 'right'
                                                            AND llevel BETWEEN 1 AND 100000)
                              ) AS t1