所以我有两个散列数组：
a = [{"b"=>123,"c"=>456}, {"b"=>456,"c"=>555}]
b = [{"c"=>456,"d"=>789}, {"b"=>222,"c"=>444}]
如何将它们与键
c的值在a和b中相等的条件连接起来意思是我希望能够连接到a['c'] == b['c']这就是我想要得到的结果：
final_array = [{"b"=>123,"c"=>456,"d"=>789}, {"b"=>456,"c"=>555}, {"b"=>222,"c"=>444}]
最佳答案
a = [{"b"=>123,"c"=>456}, {"b"=>456,"c"=>555}]
b = [{"c"=>456,"d"=>789}, {"b"=>222,"c"=>444}]
p a.zip(b).map{|h1,h2| h1["c"] == h2["c"] ? h1.merge(h2) : [h1 ,h2]}.flatten
# => [{"b"=>123, "c"=>456, "d"=>789}, {"b"=>456, "c"=>555}, {"b"=>222, "c"=>444}]
关于ruby - 如何基于相同的哈希键值合并两个哈希数组？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/17409744/