当我运行我的代码有时可以工作,但其他时候我却收到此错误:
Exception in thread "main" java.lang.StackOverflowError
at squareroot.SquareRoot.GetSquareRoot (SquareRoot.java: 9)
at squareroot.SquareRoot.GetSquareRoot (SquareRoot.java: 13)
at squareroot.SquareRoot.GetSquareRoot (SquareRoot.java: 13)`
我正在检查代码,但没有进入无限循环,请问如何解决此问题?,谢谢。
public static double GetSquareRoot(double n, double low, double high) {
double sqrt = (low + high) / 2;
if (sqrt*sqrt > n)
return GetSquareRoot(n, low, sqrt);
if (sqrt*sqrt < n)
return GetSquareRoot(n, sqrt, high);
return sqrt;
}
public static double Sqrt(double n){
return GetSquareRoot(n, 0, n);
}
public static double GetCubicRoot(double n, double low, double high) {
double cbrt = (low + high) / 2;
if (cbrt*cbrt*cbrt > n)
return GetCubicRoot(n, low, cbrt);
if (cbrt*cbrt*cbrt < n)
return GetCubicRoot(n, cbrt, high);
return cbrt;
}
public static double Cbrt(double n) {
return GetCubicRoot(n, 0, n);
}
public static void main(String[] args) {
Scanner Input = new Scanner(System.in);
double n = Input.nextDouble();
double sqrt = Sqrt(n);
double cbrt = Cbrt(n);
System.out.println("Raiz cuadrada igual a: "+ sqrt);
System.out.println("Raiz cubica igual a: "+ cbrt);
}
最佳答案
您的结果不可能达到最终条件,因为乘以数字不太可能产生确切的数字,您必须引入误差范围,因为平方根通常不精确,并且由于浮点数的限制,浮点运算使用近似值。
public static double GetSquareRoot(double n, double low, double high) {
double errorMargin = 0.001;
double sqrt = (low + high) / 2;
double diff = sqrt*sqrt - n;
if ( diff > errorMargin)
return GetSquareRoot(n, low, sqrt);
if ( -diff > errorMargin)
return GetSquareRoot(n, sqrt, high);
return sqrt;
}