python - Python BeautifulSoup抓取表

我正在尝试使用BeautifulSoup创建表格抓取。我编写了以下Python代码:

import urllib2
from bs4 import BeautifulSoup

url = "http://dofollow.netsons.org/table1.htm"  # change to whatever your url is

page = urllib2.urlopen(url).read()
soup = BeautifulSoup(page)

for i in soup.find_all('form'):
    print i.attrs['class']

我需要抓取Nome，Cognome，Email。

最佳答案

循环遍历表行(tr标记)并获取内部的单元格文本(td标记):

for tr in soup.find_all('tr')[2:]:
    tds = tr.find_all('td')
    print "Nome: %s, Cognome: %s, Email: %s" % \
          (tds[0].text, tds[1].text, tds[2].text)

打印品:

Nome:  Massimo, Cognome:  Allegri, Email:  [email protected]
Nome:  Alessandra, Cognome:  Anastasia, Email:  [email protected]
...

仅供引用，[2:] slice 是跳过两个标题行。

UPD，这是将结果保存到txt文件中的方法:

with open('output.txt', 'w') as f:
    for tr in soup.find_all('tr')[2:]:
        tds = tr.find_all('td')
        f.write("Nome: %s, Cognome: %s, Email: %s\n" % \
              (tds[0].text, tds[1].text, tds[2].text))

关于python - Python BeautifulSoup抓取表，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/18966368/