我需要对输出进行排序：
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_04092008/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_05012004/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_24072010/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_05012004/es3.sml: some content .... with words and symbols
基于日期的年份，如“050112004”，即“ggmmyyyy”，因此基于“yyyy”。
所以按以下方式排序：
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_05012004/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_05012004/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_04092008/es3.sml: some content .... with words and symbols
/dir1NameWithSpaces/dir2NameWithSpaces/dir3NameWithSpaces/File1_24072010/es3.sml: some content .... with words and symbols
谢谢
最佳答案
您可以使用sed提取排序键，对行进行排序，并使用cut删除排序键：
sed -e 's/^.*[0-9]\{4\}\([0-9]\{4\}\)/\1,&/' |
sort |
cut -d, -f2-
关于linux - Unix-对特定输出进行排序，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/16385977/