我正在使用Jackson来反序列化Product接口的许多不同实现。这些产品实现具有不同的字段,但是都具有InsuredAmount字段。该InsuredAmount类具有一个值字段和一个IAType字段。 IAType是一个标记接口,具有不同的枚举作为实现。

现在是问题所在:IAType接口的枚举实现对应于Product接口的特定实现。如何进行通用实现并告诉Jackson寻找IAType的正确实现?我是否应该在Product和IAType接口上使用通用参数来标识产品实现?是否应该在用于标识产品实现的类上使用Productable功能接口?我如何告诉 jackson 使用该实现?

我希望下面的代码可以澄清问题,我选择在此处实现Productable接口,但是也欢迎使用更好的结构来解决此问题。

@JsonPropertyOrder({"type", "someInfo"})
public class InsuredAmount implements Productable, Serializable {

    private static final long serialVersionUID = 1L;

    private IAType type;

    private String someInfo;

    public InsuredAmount() {
    }

    public InsuredAmount(IAType typeA, String someInfo) {
        this.type = typeA;
        this.someInfo = someInfo;
    }


    /* This should be on the product level, but if I can solve this problem,
    the next level will just be more of the same.
    */
    @JsonIgnore
    @Override
    public Product getProduct() {
        return Product.PROD_A;
    }

    // Getters, setters, equals, etc. omitted.
}

-
public interface Productable {

    public Product getProduct();

}

-
public enum Product {

    PROD_A, PROD_B;

}

-
@JsonDeserialize(using = IATypeDeserializer.class)
public interface IAType extends Productable {

}

-
public enum IATypeA implements IAType {

    FOO, BAR;

    @Override
    public Product getProduct() {
        return Product.PROD_A;
    }

}

-
public class IATypeDeserializer extends StdDeserializer<IAType> {

    private static final long serialVersionUID = 1L;

    public IATypeDeserializer() {
        this(null);
    }

    public IATypeDeserializer(Class<?> vc) {
        super(vc);
    }

    @Override
    public IAType deserialize(JsonParser parser, DeserializationContext context)
            throws IOException, JsonProcessingException {
        JsonNode node = parser.getCodec().readTree(parser);
        /* How to find out that the class calling the deserialization is InsuredAmountA, which
        has getProduct() method that returns PROD_A, and matches the IATypeA that also returns
        PROD_A, so I know to deserialize IATypeA, instead of other implementations of the IAType
        interface?
        */
        return IATypeA.valueOf(node.asText());
    }

}

-
public class InsuredAmountTest {

    private final ObjectMapper mapper = new ObjectMapper();

    @Test
    public void test01() throws IOException {
        InsuredAmount iaA = new InsuredAmount(IATypeA.FOO, "test it");
        String json = mapper.writeValueAsString(iaA);
        assertThat(json, is("{\"type\":\"FOO\",\"someInfo\":\"test it\"}"));
        InsuredAmount iaA2 = mapper.readValue(json, InsuredAmount.class);
        IAType type = iaA2.getType();
        assertThat(type, is(IATypeA.FOO));
        assertThat(type.getProduct(), is(Product.PROD_A));
        assertThat(iaA, is(iaA2));
    }

    @Test
    public void test02() throws IOException {
        InsuredAmount iaA = new InsuredAmount(IATypeA.BAR, "test it");
        String json = mapper.writeValueAsString(iaA);
        assertThat(json, is("{\"type\":\"BAR\",\"someInfo\":\"test it\"}"));
        InsuredAmount iaA2 = mapper.readValue(json, InsuredAmount.class);
        assertThat(iaA, is(iaA2));
    }

}

最佳答案

Jackson用最少的麻烦处理了枚举的序列化,因此您要做的就是用IAType注释@JsonTypeInfo字段:

@JsonTypeInfo(use = JsonTypeInfo.Id.MINIMAL_CLASS)
private IAType type;

然后进行测试:
public static void main(String[] args) throws IOException {
    ObjectMapper mapper = new ObjectMapper();
    String json = mapper.writeValueAsString(new InsuredAmount(IATypeA.FOO, "info"));
    System.out.println(json);
    InsuredAmount ia = mapper.readValue(json, InsuredAmount.class);
    System.out.println("Type is: " + ia.getType());
}

结果输出:
{"type":[".IATypeA","FOO"],"someInfo":"info"}
Type is: FOO

为了获得更紧凑的表示,您将必须使用自定义序列化。假设枚举名称空间中没有重叠,则可以将类型字段序列化为枚举名称。

解串器将需要知道哪些类型可用于构造,可以通过类路径发现,也可以像下面的示例中那样简单地对引用进行硬编码:
public class IATest {

    public static class IATypeSerializer extends JsonSerializer<IAType> {
        @Override
        public void serialize(IAType value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
            gen.writeString(((Enum) value).name());
        }
    }

    public static class IATypeDeserializer extends JsonDeserializer<IAType> {
        @Override
        public IAType deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
            String value = p.readValueAs(String.class);
            try {
                return IATypeA.valueOf(value);
            } catch (IllegalArgumentException e) {
                // fall through
            }
            try {
                return IATypeB.valueOf(value);
            } catch (IllegalArgumentException e) {
                // fall through
            }
            throw new JsonMappingException(p, "Unknown type '" + value + "'");
        }
    }

    public static void main(String[] args) throws IOException {
        ObjectMapper mapper = new ObjectMapper();

        // Register a module to handle serialization of IAType implementations
        SimpleModule module = new SimpleModule();
        module.addSerializer(IAType.class, new IATypeSerializer());
        module.addDeserializer(IAType.class, new IATypeDeserializer());
        mapper.registerModule(module);

        // Test
        String json = mapper.writeValueAsString(new InsuredAmount(IATypeA.FOO, "info"));
        System.out.println(json);
        InsuredAmount ia = mapper.readValue(json, InsuredAmount.class);
        System.out.println("Type is: " + ia.getType());
    }

}

哪个输出:
{"type":"FOO","someInfo":"info"}
Type is: FOO

07-26 03:10