我了解这似乎是我所见过的关于C ++和python的常见问题，但似乎找不到解决我的Java问题的解释。
附上我的程序代码，因为我还很陌生并且正在学习如何精简它，所以相当长。
import java.util.Scanner;
public class TicTacToe {
public static void main(String[] args) {
boolean gameActive = true;
boolean player1turn = true;
String board[][]= {{" ","|"," ","|"," "},{"-","-","-","-","-",},{" ","|"," ","|"," "},{"-","-","-","-","-",},{" ","|"," ","|"," "}};
commands();
printBoard(board);
while (gameActive == true) {
if (player1turn == true) {
System.out.println("\nPlayer 1, noughts turn. Please choose a position.");
} else {
System.out.println("\nPlayer 2, crosses turn. Please choose a position.");
}
String position = null;
while ("retry".equals(changePosition(position, player1turn, board))) {
Scanner keyboard = new Scanner (System.in);
position = keyboard.nextLine();
if ("help".equalsIgnoreCase(position)) {
commands();
}
else if ("turn".equalsIgnoreCase(position)){
turn(player1turn);
}
else if ("board".equalsIgnoreCase(position)){
printBoard(board);
}
else {
if (!"retry".equalsIgnoreCase(changePosition(position, player1turn, board))) {
System.out.println(changePosition(position, player1turn, board));
if (player1turn == true) {
player1turn = false;
}
else if (player1turn == false) {
player1turn = true;
}
}
}
}
}
}
public static void commands() {
System.out.println("\nPlayer 1 is noughts, O");
System.out.println("Player 2 is crosses, X");
System.out.println("\nThe board uses a grid format");
System.out.println("\"A1\" is the top-left position");
System.out.println("\"A2\" is the top-middle position");
System.out.println("\"A3\" is the top-right position");
System.out.println("\"B1\" is the middle-left position");
System.out.println("\"B2\" is the middle position");
System.out.println("\"B3\" is the middle-right position");
System.out.println("\"C1\" is the bottom-left position");
System.out.println("\"C2\" is the bottom-middle position");
System.out.println("\"C3\" is the bottom-right position");
System.out.println("\n\"help\" will reveal this help message");
System.out.println("\"board\" will reveal the board");
System.out.println("\"turn\" will reveal whos turn it is");
}
public static void turn(boolean player1turn) {
if (player1turn == true) {
System.out.println("\nPlayer 1, noughts turn.");
} else {
System.out.println("\nPlayer 2, crosses turn.");
}
}
public static void printBoard(String[][] board) {
System.out.print("\n");
for (int x=0;x<5;x++) {
for (int y=0;y<5;y++) {
System.out.print(board[x][y]+"");
}
System.out.println();
}
}
public static String changePosition(String position, boolean player1turn, String[][] board) {
if (("A1".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[0][0])) {
board[0][0] = "O";
return board[0][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B1".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[2][0])) {
board[2][0] = "O";
return board[2][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C1".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[4][0])) {
board[4][0] = "O";
return board[4][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("A2".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[0][2])) {
board[0][2] = "O";
return board[0][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B2".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[2][2])) {
board[2][2] = "O";
return board[2][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C2".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[4][2])) {
board[4][2] = "O";
return board[4][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("A3".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[0][4])) {
board[0][4] = "O";
return board[0][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B3".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[2][4])) {
board[2][4] = "O";
return board[2][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C3".equalsIgnoreCase(position)) && (player1turn == true)) {
if (" ".equals(board[4][4])) {
board[4][4] = "O";
return board[4][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("A1".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[0][0])) {
board[0][0] = "X";
return board[0][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B1".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[2][0])) {
board[2][0] = "X";
return board[2][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C1".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[4][0])) {
board[4][0] = "X";
return board[4][0];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("A2".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[0][2])) {
board[0][2] = "X";
return board[0][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B2".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[2][2])) {
board[2][2] = "X";
return board[2][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C2".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[4][2])) {
board[4][2] = "X";
return board[4][2];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("A3".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[0][4])) {
board[0][4] = "X";
return board[0][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("B3".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[2][5])) {
board[2][4] = "X";
return board[2][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else if (("C3".equalsIgnoreCase(position)) && (player1turn == false)) {
if (" ".equals(board[4][4])) {
board[4][4] = "X";
return board[4][4];
} else {
System.out.println("That spot is taken please choose another place");
return "retry";
}
}
else {
if ((position == null) || ("help".equalsIgnoreCase(position)) || ("turn".equalsIgnoreCase(position)) || ("board".equalsIgnoreCase(position))) {
return "retry";
} else {
System.out.println("Error please enter a valid position found by entering \"help\" ");
return "retry";
}
}
}
}
据我所知，问题涉及我的长度changePosition（）方法。如果我在控制台“ A1”中输入，结果将是：
Player 1, noughts turn. Please choose a position.
A1
That spot is taken please choose another place
retry
That spot is taken please choose another place
board
O| |
-----
| |
-----
| |
这使我感到困惑，因为似乎if块实际上已触发并导致board [0] [0]被更改，但是由于某种原因必须移至else块并将消息打印到控制台并返回“重试”。
我尝试将if块内的返回值更改为标准字符串，例如“ success”，但这似乎无法解决问题。另外，当我将鼠标悬停在返回类型上时，IDE会将其标识为返回点。我确信（我有信心）使用的语法正确。
我希望这是我冗长的代码存在的问题，我相信这对你们所有人来说都是戈尔。
谢谢。
最佳答案
问题是您在此循环的每次迭代中多次调用changePosition方法：
while ("retry".equals(changePosition(position, player1turn, board))) {
Scanner keyboard = new Scanner (System.in);
position = keyboard.nextLine();
if ("help".equalsIgnoreCase(position)) {
commands();
}
else if ("turn".equalsIgnoreCase(position)){
turn(player1turn);
}
else if ("board".equalsIgnoreCase(position)){
printBoard(board);
}
else {
if (!"retry".equalsIgnoreCase(changePosition(position, player1turn, board))) {
System.out.println(changePosition(position, player1turn, board));
if (player1turn == true) {
player1turn = false;
}
else if (player1turn == false) {
player1turn = true;
}
}
}
}
}
首先，它在
while循环的条件下被调用：while（“ retry” .equals（changePosition（position，player1turn，board）））
但是由于参数位置一开始仍然为空，因此它仅会返回
"retry"并在首次发生时进入循环。输入职位后，请在此处调用方法：
如果（！“ retry” .equalsIgnoreCase（changePosition（position，player1turn，
板）））
如果现货是免费的，它将正常工作并且不返回
"retry"，因此输入if语句块。这就是您的情况，并且从那一刻开始实际填充A1。然后，您立即在下一行再次调用该方法：
System.out.println（changePosition（position，player1turn，board））;
但是由于现在A1已被占用，这一次将输出错误“该地点已被占用，请选择另一个地方”并返回您也打印的
"retry"错误。然后在下一次迭代的开始再次检查循环条件时，再次调用该方法。并且由于您现在使用相同的参数第三次调用它，它将再次输出错误并返回
"retry"作为返回值，从而再次进入循环。解决方案是每次迭代仅调用一次函数，然后保存返回值并进行处理。
您还应该使用do-while循环，因为它始终应该至少运行一次：
String changePositionResult = null;
do {
final Scanner keyboard = new Scanner(System.in);
position = keyboard.nextLine();
if ("help".equalsIgnoreCase(position)) {
commands();
} else if ("turn".equalsIgnoreCase(position)) {
turn(player1turn);
} else if ("board".equalsIgnoreCase(position)) {
printBoard(board);
} else {
changePositionResult = changePosition(position, player1turn, board);
if (!"retry".equalsIgnoreCase(changePositionResult)) {
System.out.println(changePositionResult);
if (player1turn == true) {
player1turn = false;
} else if (player1turn == false) {
player1turn = true;
}
}
}
} while ("retry".equals(changePositionResult));
关于java - 如果满足条件并激活了条件，则阻止打印，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/48585418/