因此,当我继续构建我的自动索具脚本时,我遇到了我预期难以解决的三个问题中的第二个。这可能是一个非常简单的答案:但脚本本身非常易于使用,首先点击生成代理定位器,然后点击构建脊椎关节:但问题出现在构建 IK 控件按钮上,它足够好地复制绑定(bind)关节并且重命名第一个:但我无法像绑定(bind)关节那样正确地增加数字:如果你扩展它,它只会给你名为“spine__IK”的 child 任何帮助总是很感激:
'''
import DS_hybrid_spineOmatic_V1
reload (DS_hybrid_spineOmatic_V1)
DS_hybrid_spineOmatic_V1.gui()
'''
import re
import maya.cmds as cmds
import maya.mel as mel
if cmds.window("spineWin", exists =True):
cmds.deleteUI("spineWin", window = True)
myWindow = cmds.window("spineWin",t='DS_hybrid_spineOmatic_V1',w=200, h=500, toolbox=True)
column = cmds.columnLayout(adj=True)
'''
To DO:
-You're going to have a series of scrips splitting into an IKFK spine and a ribon spine: this script will build the IKFK spine
-make build spine joints orient joint chain
'''
def gui():
cmds.button( label="Generate Spine Proxy Locators", c = buildProxies)
cmds.separator( w=200, h=3)
cmds.button( label="Build Spine Joints", c = buildJointChain)
cmds.separator( w=200, h=3)
cmds.button( label="Build IK Controls", c = createIKcontrols)
cmds.separator( w=200, h=9)
cmds.setParent('..')
cmds.showWindow(myWindow)
def buildProxies(*args):
locAmount = 2
for i in range(locAmount):
countLoc = i+1
spaceLoc = cmds.spaceLocator(n = 'spineLoc_{}_PRX'.format(countLoc), p = [0,i*2.5,0])
cmds.makeIdentity(spaceLoc, a=1, t=1)
mel.eval('CenterPivot;')
cmds.parent('spineLoc_2_PRX','spineLoc_1_PRX')
def buildJointChain(*args):
cmds.select(cl=True) #this line clears your selection
#this For in range loop creates equidistant joints between the 2 proxy locators
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
countJnt = 7
startLoc = "spineLoc_1_PRX" #this is where the joint chain starts
endLoc = "spineLoc_2_PRX" #this is where the joint chain ends
jntPosSteps = 1.0/(countJnt-1) # Will use count to calculate how much it should increase percentage by each iteration. Need to do -1 so the joints reach both start and end points.
jntPerc = 0 # This will always go between a range of 0.0 - 1.0, and we'll use this in the constraint's weights.
for jNum in range(countJnt):
jntInc = jNum
jnt = cmds.joint(n = 'spineJnt_{}_Bound'.format(jntInc))
cmds.setAttr(jnt + ".displayLocalAxis", True) #display the local rotation axis of the joint
jntConstraint = cmds.pointConstraint(startLoc, jnt, weight=1.0 - jntPerc)[0] # Apply 1st constraint, with inverse of current percentage.
cmds.pointConstraint(endLoc, jnt, weight=jntPerc)
cmds.delete(jntConstraint) #constraint is now no longer neccisary
jntPerc += jntPosSteps #Increase percentage for next iteration
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#this will orient the joint chain(build later)
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
cmds.select(cl=True)
cmds.group(n='skeletonGrp',empty=True,world=True)
cmds.parent('spineJnt_0_Bound','skeletonGrp')
cmds.delete('spineLoc_1_PRX')
def createIKcontrols(*args):
#create spine control curves
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#create duplicate joint chain
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
ikName = 'spineJnt_*_IK'
ikChain = cmds.duplicate('spineJnt_0_Bound', n='spineJnt_0_IK')[0]
cmds.parent(ikChain,world=True)
ikList = cmds.listRelatives(ikChain,ad=True,pa=True)
for name in ikList:
cmds.rename(name, ikName)
print(ikList)
#//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#create IK spline handle for joint chain
我只需要脚本正确并按顺序重命名重复的关节链
最佳答案
您不能使用通配符来重命名 cmds.rename(name, ikName)
,其中 ikName 为 'spineJnt_*_IK' 将导致 'spineJnt__IK',因为在 Maya 中 * 是无效字符,将被下划线替换。但是你可以这样做:
for idx, name in enumerate(ikList):
cmds.rename(name, 'spineJnt_{0}_IK'.format(idx))
print(ikList)
什么导致或多或少正确的命名。这里的问题是 listRelatives 在父节点之前首先为您提供叶节点。所以你的编号将是相反的。这可以通过反转 id 来解决:
cmds.rename(name, 'spineJnt_{0}_IK'.format(len(ikList) - idx))
这应该会给你一个更好的结果。
关于python - 玛雅 Python : rename duplicated joint children,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/60543702/