我使用命令行参数输入指令。我通过了包含有关如何运行类的信息的文本文件所在的位置。在一种情况下,程序必须像发生错误一样动作,并且需要关闭。我能够做到这一点。最后该对象也被serlized。现在,我必须使用相同的ser文件来重新启动程序,并从与上次使用restore类关闭的位置相同的位置启动它。由于某些奇怪的原因,我得到了nullpinterException。我已标记出我在哪里得到该错误。
public static void main(String[] args) throws Exception {
try {
String option = args[0];
String filename = args[1];
if (!(option.equals("-f")) && !(option.equals("-d"))) {
System.out.println("Invalid option");
printUsage();
}
System.out.println(filename);
GreenhouseControls gc = new GreenhouseControls();
if (option.equals("-f")) {
gc.addEvent(gc.new Restart(0, filename));
try {
FileOutputStream fileOut = new FileOutputStream("/Users/Arsalan Khan/Google Drive/cosc/TME/src/dumpout.ser");
ObjectOutputStream out = new ObjectOutputStream(fileOut);
out.writeObject(gc);
out.close();
} catch (IOException i) {
i.printStackTrace();
}
}
gc.run();
// serialization try catch
// the instance where the error occored is also passed to
if (option.equals("-d")) {
// GreenhouseControls.main(GreenhouseControls.java:567)
Restore re = new Restore(filename);
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Invalid number of parameters");
printUsage();
e.printStackTrace();
}
}
public class Restore {
String fileNameNew;
public Restore(String fileName) {
this.fileNameNew = fileName;
}
// print the state of the save to the console
{// deserilize dump.out
try {
// here at Restore.<init>(Restore.java:17)
FileInputStream fileIn = new FileInputStream(fileNameNew);
ObjectInputStream in = new ObjectInputStream(fileIn);
// it has to be cast to GreenhouseControls since everything saved in
// a file is retrieved as an object
GreenhouseControls readGreen = (GreenhouseControls) in.readObject();
in.close();
System.out.println(readGreen);
// since we are trying to fix the error in gc we will pass its
// instance and use fixable to fix it
readGreen.getFixable((Integer) readGreen.errorCode);
} catch (IOException | ClassNotFoundException i) {
i.printStackTrace();
}
}
// restart from where it left the program
// run fix window and power on to fix problems
;
}
最佳答案
此时的例外只能是fileNameNew
是null
。而且不会扔在那里。它必须在构造函数链或它调用的某些方法中抛出。
在尝试对任何内容进行反序列化之前,问题就已经发生了,并且(实际上)与反序列化过程无关。
实际上,fileNameNew
是null
的原因是您试图在实例初始化程序块中进行操作。 (坏主意...)该块在Restore
构造函数主体之前执行,并且此时,fileNameNew
字段仍将处于其默认的初始化状态。
解决方案是将实例初始化程序块中的代码放入构造函数中,以便在this.fileNameNew = fileName;
之后执行