对于我的游戏,我将用户玩过的游戏数量存储在内部存储器中的文件中。这非常有效,直到存储了195之后,无论玩了多少游戏,它都不会增加。
public void saveNumGames(){
Log.d("saveNumGames", "Called");
int numGames;
File numGamesFile = new File(mainActivity.getFilesDir(), "numGames");
try {
BufferedInputStream BIS = new BufferedInputStream(new FileInputStream(numGamesFile));
numGames = BIS.read();
}catch (Exception e) {
e.printStackTrace();
numGames = 0;
}
try{
numGames++;
Log.d("numGames", Integer.toString(numGames));
FileOutputStream fos = new FileOutputStream(numGamesFile);
PrintWriter PW = new PrintWriter(new OutputStreamWriter(fos));
PW.write(numGames);
PW.flush();
PW.close();
if(numGames==12){
Games.Achievements.unlock(MainActivity.apiClient, "CgkIlcXhyp4YEAIQDA");
} else if(numGames==50){
Games.Achievements.unlock(MainActivity.apiClient, "CgkIlcXhyp4YEAIQDQ");
}
}catch (Exception e){
e.printStackTrace();
}
}
我的想法是,这是因为数字195是可存储在字节(或位?)中的最大值。如果是这样,我应该怎么做才能防止此数字上限发生。
最佳答案
首先您使用了两种错误的方法。首先是numGames = BIS.read(); read()方法设计为仅读取一个字节。另一个方法PW.write(numGames)方法write哪个参数int指定要写入的字符。
它应该工作:
public static void saveNumGames() {
Log.d("saveNumGames", "Called");
int numGames;
File numGamesFile = new File(mainActivity.getFilesDir(), "numGames");
try {
numGames = new Integer(new String(Files.readAllBytes(Paths.get(mainActivity.getFilesDir() + "numGames"))));
} catch (Exception e) {
e.printStackTrace();
numGames = 0;
}
try (FileOutputStream fos = new FileOutputStream(numGamesFile)) {
numGames++;
Log.d("numGames", Integer.toString(numGames));
PrintWriter PW = new PrintWriter(fos);
PW.write(String.valueOf(numGames));
PW.flush();
PW.close();
if (numGames == 12) {
Games.Achievements.unlock(MainActivity.apiClient, "CgkIlcXhyp4YEAIQDA");
} else if (numGames == 50) {
Games.Achievements.unlock(MainActivity.apiClient, "CgkIlcXhyp4YEAIQDQ");
}
} catch (Exception e) {
e.printStackTrace();
}
}