python - 跟踪计数器嵌套循环

我目前正在为学校做一次小作业。

我需要打印当前火车所在的当前车站以及列表中剩余的车站。

我使用了嵌套的for循环，但无法获取内部的for循环以正常工作。我是否需要使用+=1创建变量？

我的代码：

train_station=['Amsterdam-Central','Amsterdam-Amstel','Utrecht']

for x in train_station:
    print("Current station is: "+x)
    print("Stations to go: ")

    begin=0


    for y in range(begin,3,1):
        print(train_stations[y])

我的输出：

Current station is: Amsterdam-Central
Stations to go:
Amsterdam-Central
Amsterdam-Amstel
Utrecht

Current station is: Amsterdam-Amstel
Stations to go:
Amsterdam-Central
Amsterdam-Amstel
Utrecht

Current station is: Utrecht
Stations to go:
Amsterdam-Central
Amsterdam-Amstel
Utrecht

最佳答案

差不多完成了，您只需要在每次迭代中增加begin即可。

train_station=['Amsterdam-Central','Amsterdam-Amstel','Utrecht']
begin = 0

for x in train_station:
    print("Current station is: "+x)
    print("Stations to go: ")

    begin += 1

    for y in range(begin, 3, 1):
        print(train_station[y])

还有一个更Python化的解决方案：

for i, x in enumerate(train_station, 1):
    print("Current station is: "+x)
    print("Stations to go: ")

    for y in train_station[i:]:
        print(y)