c - a [1]和b [1]有什么区别？

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我正在学习c指针。我了解到数组名称本身就是一个指针。

int a[5]={ 1 , 2 , 3 , 4 , 5 };
int *b = &a;

我的理解：
    a [5]-> a包含基址
    考虑一个在0x100的位置
    因此a [5] = 0x100 +（5 * size_of_integer）
    = 0x100 +（5 * 4）
    = 0x100 +（20）
    = 0x120

b = &a; // b = 0x100b[0] = 0x100b[1] = 0x104

a [0]和b [0]有什么区别？
（我是初学者，我可能错了）

最佳答案

a是int a[5]数组。 a指向第一个（a[0]）元素。 b是a的指针。您可以使用以下代码进行检查：

#include <stdio.h>

int main()
{

    int a[5] = {1, 2, 3, 4, 5};
    int *b = &a;
    printf("a %p\n", a);         // (1) address of a array.
    printf("a[0] %p\n", &a[0]);  // (2) address of first element of a array
    printf("b %p\n", b);         // (3) address of b

    printf("b[2] %p\n", &b[2]);    // (4) means [address of b] + 2 * sizeof(int)
    printf("a[2] %p\n", &a[2]);    // (5) third element of array

    return 0;
}

（1）=（2）=（3）和（4）=（5）

还要b[0] = 1不寻址（如您的示例中的0x100）和b[1] = 2。

printf("b[0] %d\n", &b[0]);
printf("b[1] %d\n", &b[1]);