django - 具有多个ID的DjangoFilterBackend

我想用django-filter过滤模型。如果我按一个ID进行过滤，则效果很好：

http://localhost:8000/accommodations?accommodationType_id=1

但是我不知道如何通过多个ID进行过滤。

http://localhost:8000/accommodations?accommodationType_id=1,2

我实际的ViewSet看起来像这样：

class AccommodationViewSet(viewsets.ReadOnlyModelViewSet):
    """
        REST API endpoint for 'accommodation' resource
    """
    queryset = Accommodation.objects.all()
    serializer_class = AccommodationSerializer
    filter_backends = (filters.DjangoFilterBackend,)
    filter_fields = ('accommodationType_id', 'name')

我希望有一个解决方案。

最佳答案

我为我的问题找到了以下解决方案:)

https://gist.github.com/aBuder/654fb945f085b17358d8

from webapp.serializers import *
from rest_framework import viewsets
from rest_framework import filters
from django_filters import Filter, FilterSet


class ListFilter(Filter):
    def filter(self, qs, value):
        if not value:
            return qs

        # For django-filter versions < 0.13, use lookup_type instead of lookup_expr
        self.lookup_expr = 'in'
        values = value.split(',')
        return super(ListFilter, self).filter(qs, values)


class AccommodationFilter(FilterSet):
    ids = ListFilter(name='id')
    accommodationType_ids = ListFilter(name='accommodationType_id')

    class Meta:
        model = Accommodation
        fields = ['ids', 'accommodationType_ids']


class AccommodationViewSet(viewsets.ReadOnlyModelViewSet):
    """
        REST API endpoint for 'accommodation' resource
    """
    queryset = Accommodation.objects.all()
    serializer_class = AccommodationSerializer
    filter_backends = (filters.DjangoFilterBackend,)
    filter_class = AccommodationFilter

关于django - 具有多个ID的DjangoFilterBackend，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/31029792/