java - Java实现间隔解析int

我将如何实现间隔解析int以增加线性整数数组中的增量？
并还给它

public class Sequence {
    /*Generate an array representing a linear sequence of N values specified by the start value and the interval example,interval(6, 2, 3) would produce {2,5,8,11,14,17}*/
    public int[] Linear(int N, int start, int interval){
        int interval = Integer.parseInt(args[0]);
        for (int i = 1; i<= N; i++);
        i = i + interval;


    }

    //Generate an array of the first N values of the Fibonacci sequence (1,1,2,3,5,8,13,21,...). Assume N > 2
    public static int[] fibonacci(int N){
        int[] fibo = new int [N + 1];
        fibo[0] = 1;
        fibo[1] = 1;
        for (int i = 2; i<= N; i++)
            fibo[i]= fibo[i-1] + fibo[i-2];
        //  int[] x = fibo;
        return fibo;

    }

    public static void main(String[] args) {

        int N = Integer.parseInt(args[0]);
        //fibonacci(N);



        for (int i = 1; i <= N; i++ )

            System.out.println(fibonacci(i));


    }
}

最佳答案

这是您的Linear方法应如下所示：

public int[] Linear(int N, int start, int interval){

    // First declare the array.
    int[] linearArray = new int[N];

    // Declare something to hold the next value
    // The first value will be "start"

    int value = start;

    // Then, iterate over a for loop
    for (int i = 0; i< N; i++){
        // assign the current value to the current indexed element in the array
        linearArray[i] = value;

        // compute next value
        value = value + interval;
    }

    // Finally, return your array
    return linearArray;
}