我在使用以下代码时遇到问题,我创建了两个带有onClickListener的按钮。
它对于Button来说效果很好-btnAbout,我正尝试使用另一种方法来处理btnIntro,而不是使用findViewById(...)方法,但是单击btnIntro时将不执行该语句。
为什么会这样?
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.Toast;
public class TestActivity extends Activity {
private final String TAG = "tag";
private Button btnIntro;
private Button btnAbout;
private View layoutView;
private ViewWrapper wrapper;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
btnAbout = (Button) findViewById(R.id.btnAbout);
if (btnIntro == null) {
LayoutInflater inflator = getLayoutInflater();
layoutView = inflator.inflate(R.layout.main, null, false);
wrapper = new ViewWrapper(layoutView);
layoutView.setTag(wrapper);
} else {
wrapper = (ViewWrapper) layoutView.getTag();
}
btnIntro = wrapper.getButton();
Log.e(TAG, Integer.toHexString(layoutView.getId()) + "");
Log.e(TAG, btnIntro.getText().toString());
btnIntro.setOnClickListener(new OnClickListener() {
{
Log.e(TAG, "static");
}
@Override
public void onClick(View arg0) {
Log.e(TAG, "btnIntro clicked");
Toast.makeText(TestActivity.this, "btnIntro", Toast.LENGTH_SHORT)
.show();
}
});
btnAbout.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
Log.e(TAG, "btnAbout clicked");
Toast.makeText(TestActivity.this, "about", Toast.LENGTH_SHORT).show();
}
});
}
class ViewWrapper {
View base;
Button btn1;
ViewWrapper(View base) {
this.base = base;
}
Button getButton() {
if (btn1 == null) {
btn1 = (Button) base.findViewById(R.id.btnIntro);
Log.e(TAG, btn1.getText().toString());
}
return btn1;
}
}
}
main.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/MAIN_LAYOUT_XML"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="30dip">
<TextView
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="Test" />
<Button
android:id="@+id/btnIntro"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="btnIntro" />
<Button
android:id="@+id/btnAbout"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="btnAbout" />
</LinearLayout>
最佳答案
问题在于您使用不同的内容视图来获取按钮,一个在调用setContentView()时创建,第二个通过调用inflator.infate()创建。因此,您获得的按钮将放置在不同的内容视图中(仅显示其中一个-由setContentView创建)。尝试改用:
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
LayoutInflater inflator = getLayoutInflater();
layoutView = inflator.inflate(R.layout.main, null, false);
setContentView(layoutView);
//..anything you need..
}