python - 如何减去QPainterPaths，QPolygon？

我试图了解path1.subtracted(path2)的工作原理。


我有路径1和路径2：
我正在使用path3=path1.subtracted(path2)获取path3。
为什么我没有想要的道路？图片：


这是代码：

from PyQt5.QtCore import QPointF
from PyQt5.QtCore import QRectF, Qt
from PyQt5.QtGui import QPainterPath, QPen
from PyQt5.QtGui import QPolygonF
from PyQt5.QtWidgets import QApplication, QGraphicsScene, \
    QGraphicsView, QPushButton, QWidget, \
    QVBoxLayout, QGraphicsItem, QGraphicsPathItem, QGraphicsRectItem

class Window(QWidget):
    scene = None

    def __init__(self):
        QWidget.__init__(self)
        self.view = View(self)
        self.button = QPushButton('Clear View', self)
        self.button.clicked.connect(self.handleClearView)
        layout = QVBoxLayout(self)
        layout.addWidget(self.view)
        layout.addWidget(self.button)

    def handleClearView(self):
        self.view.scene.clear()


class View(QGraphicsView):
    def __init__(self, parent):

        self.scribing = False
        self.erasing = False
        QGraphicsView.__init__(self, parent)
        self.scene = QGraphicsScene()
        self.setScene(self.scene)

    def resizeEvent(self, QResizeEvent):
        self.setSceneRect(QRectF(self.viewport().rect()))

    def mousePressEvent(self, event):

        if event.buttons() == Qt.LeftButton:
            self.scribing = True

            self.path1 = QPainterPath()
            self.path2 = QPainterPath()

            self.polygon1 = QPolygonF()
            self.polygon1.append(QPointF(100,100))
            self.polygon1.append(QPointF(100, 300))
            self.polygon1.append(QPointF(300, 300))
            self.polygon1.append(QPointF(300, 100))

            self.polygon2 = QPolygonF()
            self.polygon2.append(QPointF(300,100))
            self.polygon2.append(QPointF(300, 300))
            self.polygon2.append(QPointF(100, 300))

            self.path1.addPolygon(self.polygon1)
            self.path2.addPolygon(self.polygon2)

            path3 = self.path1.subtracted(self.path2)

            # self.scene.addPath(self.path1, QPen(Qt.blue))
            # self.scene.addPath(self.path2, QPen(Qt.green))
            self.scene.addPath(path3, QPen(Qt.red))


        if event.buttons() == Qt.RightButton:
            self.erasing = True


    def mouseMoveEvent(self, event):

        if (event.buttons() & Qt.LeftButton) and self.scribing:
            if self.free_draw_item:
                pass

        if event.buttons() & Qt.RightButton and self.erasing:
            pass

    def mouseReleaseEvent(self, event):
        self.scribing = False
        self.erasing = False

        # if self.eraser_item != None:
        #     self.scene.removeItem(self.eraser_item)
        # if self.free_draw_item != None:
        #     self.free_draw_item.setSelected(True)


if __name__ == '__main__':
    import sys

    app = QApplication(sys.argv)
    window = Window()
    window.resize(640, 480)
    window.show()
    sys.exit(app.exec_())

在此示例中，我正在使用QPolygonF。我也尝试创建p1=QPainterPath()，p2=QPainterPath()并减去以获得p3。但是，没有成功，就无法获得相同的结果。

最佳答案

QpainterPath.subtracted()不会减去路径元素，但会减去路径面积，
see documentation

如果使用QpainterPath::operator-()，则具有相同的效果：

        # path3 = self.path1.subtracted(self.path2)
        path3 = self.path1 – self.path2

您可以通过类似这样的方式来识别路径的元素

        c = path3.elementCount()
        for i in range(c):
            e = path3.elementAt(i)
            print('Element-nr.: ',  i, 'Type: ',  e.type, 'x: ',   e.x,  'y: ',  e.y)   # type: 0 = MoveTo, 1 = LineTo

我认为，您必须编写自己的方法，该方法根据path1和path2的元素创建path3。

关于python - 如何减去QPainterPaths，QPolygon？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/39726477/