java - 尽管我修改了该字段，但Netbeans建议将一个字段转换为final

首先，这里是相关代码：

public class AtCounter
{
    private char[][] atMat;
    private int atCount;

    public AtCounter()
    {
        atCount=0;
        atMat= new char[][]{{'@','-','@','-','-','@','-','@','@','@'},
                            {'@','@','@','-','@','@','-','@','-','@'},
                            {'-','-','-','-','-','-','-','@','@','@'},
                            {'-','@','@','@','@','@','-','@','-','@'},
                            {'-','@','-','@','-','@','-','@','-','@'},
                            {'@','@','@','@','@','@','-','@','@','@'},
                            {'-','@','-','@','-','@','-','-','-','@'},
                            {'-','@','@','@','-','@','-','-','-','-'},
                            {'-','@','-','@','-','@','-','@','@','@'},
                            {'-','@','@','@','@','@','-','@','@','@'}};

    }

    public int countAts(int r, int c)
    {

        if(r<atMat.length && c<atMat[0].length && r>=0 && c>=0 && atMat[r][c]=='@')
        {
            atMat[r][c]='X';
            atCount++;
        }
        else
            if(r-1<atMat.length && r-1>=0)
                countAts(r-1,c);
        else
                if(r+1<atMat.length && r+1>=0)
                    countAts(r+1,c);
        else
                    if(c-1<atMat[0].length && c-1>=0)
                        countAts(r,c-1);
        else
                        if(c+1<atMat[0].length && c+1>=0)
                            countAts(r,c+1);
        return atCount;

    }

请注意，countsAts方法包含atMat[r][c]='X';行，该行更改了二维数组中元素的值。尽管如此，在private char[][] atMat;行上，Netbeans给我警告“ Field atMat可能是最终的”。如果我修改其值，为什么该字段可以是最终值？它与我当前正在修改的代码中的位置有关吗？ Netbeans是否被窃听（怀疑）？如果有人可以解释警告，我将不胜感激！

最佳答案

您可以更改名称为atMat的对象的内容。 atMat是参考。引用本身可以成为最终的。