Groovy版本2.4.8
Grails 2.5.1版
我试图使用like子句从Advisor表中提取行,并且如果该方法中传递了Firm名称,那么我只想从该Firm中提取Advisor。
我构造了两个查询,但没有Firming组件,该组件工作正常,但是当我取消注释设置Firmware的行以测试第二个查询运行时,出现以下异常org.springframework.orm.hibernate4.HibernateQueryException: Not all named parameters have been set: [firm] [from Advisor a where lower(a.firstName) like:keystrokes OR lower(a.lastName) like:keystrokes AND a.firm.name = :firm];
码:
def getAdvisorsForKeystrokes(String keystrokes, String firm, int maxResults) {
List<Advisor> advisors;
firm = "Test Firm Name"
if(firm.allWhitespace) {
advisors = Advisor.findAll('from Advisor a where lower(a.firstName) like:keystrokes OR lower(a.lastName) like:keystrokes', [keystrokes:keystrokes + '%'], [max:maxResults])
} else {
advisors = Advisor.findAll('from Advisor a where lower(a.firstName) like:keystrokes OR lower(a.lastName) like:keystrokes AND a.firm.name = :firm', [keystrokes:keystrokes + '%'], [firm:firm], [max:maxResults])
}
return advisors
}
类:
class Advisor {
String firstName
String lastName
String fullName
String city
String state
Firm firm
static belongsTo = [Case, Firm]
static hasMany = [cases:Case]
static constraints = {
}
}
class Firm {
String name
static constraints = {
}
}
如果有人对问题出在哪里有什么想法,或者对解决方案感到惊奇,那就谢谢!
编辑:
我知道它可以像下面这样重写并工作,但是我尝试了许多不同的方式在一个查询中执行此操作,但令我感到困扰的是,我一直无法找到一种使其工作的方式。
def getAdvisorsForKeystrokes(String keystrokes, String firm, int maxResults) {
List<Advisor> advisors;
advisors = Advisor.findAll('from Advisor a where lower(a.firstName) like:keystrokes OR lower(a.lastName) like:keystrokes', [keystrokes:keystrokes + '%'], [max:maxResults])
if(!firm.allWhitespace) {
def firmModel = Firm.findByName(firm)
advisors = advisors.findAll{ adv ->
adv.firm == firmModel
}
}
return advisors
}
最佳答案
您应该在同一 map 中设置两个参数,如下所示:
advisors = Advisor.findAll('from Advisor a where lower(a.firstName) like:keystrokes OR lower(a.lastName) like:keystrokes AND a.firm.name = :firm', [keystrokes:keystrokes + '%', firm:firm], [max:maxResults])