arrays - 按行号组合3个数组

有没有一种方法可以在R中组合三个数组，以使第一个数组的第一行紧随第二个数组的第一行，然后是第三个数组的第三行？因此，如果我运行以下代码：

> number1<-rbind(rep("A",3), rep("B",3), rep("C",3))
> number1
     [,1] [,2] [,3]
[1,] "A"  "A"  "A"
[2,] "B"  "B"  "B"
[3,] "C"  "C"  "C"
> number2<-rbind(rep(1,3), rep(2,3), rep(3,3))
> number2
     [,1] [,2] [,3]
[1,]    1    1    1
[2,]    2    2    2
[3,]    3    3    3
> number3<-rbind(rep("X",3), rep("Y",3), rep("Z",3))
> number3
     [,1] [,2] [,3]
[1,] "X"  "X"  "X"
[2,] "Y"  "Y"  "Y"
[3,] "Z"  "Z"  "Z"

结果将如下所示：

      [,1] [,2] [,3]
 [1,] "A"  "A"  "A"
 [2,] "1"  "1"  "1"
 [3,] "X"  "X"  "X"
 [4,] "B"  "B"  "B"
 [5,] "2"  "2"  "2"
 [6,] "Y"  "Y"  "Y"
 [7,] "C"  "C"  "C"
 [8,] "3"  "3"  "3"
 [9,] "Z"  "Z"  "Z"

我已经尝试过融化，但是无法正常工作。

最佳答案

您可以尝试以下方法：

> matrix(t(cbind(number1,number2,number3)),ncol=3, byrow=T)
#      [,1] [,2] [,3]
# [1,] "A"  "A"  "A"
# [2,] "1"  "1"  "1"
# [3,] "X"  "X"  "X"
# [4,] "B"  "B"  "B"
# [5,] "2"  "2"  "2"
# [6,] "Y"  "Y"  "Y"
# [7,] "C"  "C"  "C"
# [8,] "3"  "3"  "3"
# [9,] "Z"  "Z"  "Z"

关于arrays - 按行号组合3个数组，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32233623/