例如
我有一个名为tempobj
的对象,下面是tempobj[0]
和tempobj[1]
样本数据。
我想添加其他信息,例如该对象的名称和状态
tempobj ["info"]["name"] = "title";
tempobj ["info"]["id"] = "23243";
但是当我做
stringify
时,jQuery忽略了这个值...我怎样才能将这样的数据添加到这种结构中。 [
[{
"name": "Breakfast",
"value": "buffalo strip ",
"check": 0
}, {
"name": "snack ",
"value": "pecan pie butter",
"check": 0
}, {
"name": "dessert",
"value": "chocolate zucchani brownie",
"check": 0
}],
[{
"name": "Breakfast",
"value": "Stir Fried Kale and Baccon ",
"check": 1
}, {
"name": "snack ",
"value": "Smoked Salmon nori roll "
}, {
"name": "dessert",
"value": "Apple muffins"
}]
最佳答案
tempobj
是一个数组([]
)。
当您尝试使用以下方法设置一些值时:
tempobj["info"]["name"] = "title";
tempobj["info"]["id"] = "23243";
您将其视为对象(
{}
)。如果要向
tempobj
添加一些数据,则必须像这样更改其结构,例如:{
"info": {
"name": "title",
"id": "23243"
},
"items": [
[{
"name": "Breakfast",
"value": "buffalo strip ",
"check": 0
}, {
"name": "snack ",
"value": "pecan pie butter",
"check": 0
}, {
"name": "dessert",
"value": "chocolate zucchani brownie",
"check": 0
}],
[{
"name": "Breakfast",
"value": "Stir Fried Kale and Baccon ",
"check": 1
}, {
"name": "snack ",
"value": "Smoked Salmon nori roll "
}, {
"name": "dessert",
"value": "Apple muffins"
}]
]
}
这是一个示例:
var tempobj = {
items: [
[{
"name": "Breakfast",
"value": "buffalo strip ",
"check": 0
}, {
"name": "snack ",
"value": "pecan pie butter",
"check": 0
}, {
"name": "dessert",
"value": "chocolate zucchani brownie",
"check": 0
}],
[{
"name": "Breakfast",
"value": "Stir Fried Kale and Baccon ",
"check": 1
}, {
"name": "snack ",
"value": "Smoked Salmon nori roll "
}, {
"name": "dessert",
"value": "Apple muffins"
}]
]
}
tempobj.info = {
name: 'title',
id: '23243'
};
// Another way:
//tempobj.info = {};
//tempobj.info.name = 'title';
//tempobj.info.id = '23243';
console.log(JSON.stringify(tempobj));