我对此代码有疑问:

package javaapplication16;
import java.io.InputStream;
import javax.swing.JOptionPane;
import sun.audio.AudioPlayer;
import sun.audio.AudioStream;
public class JavaApplication16 {
    public static void main(String[] args) {
        NewJFrame n = new NewJFrame();
        n.setVisible(true);
        InputStream is;
        is = this.getClass().getClassLoader().getResourceAsStream("samp.wav");
        try {
            AudioStream audioStream;
            audioStream = new AudioStream(is);
            AudioPlayer.player.start(audioStream);
        } catch (Exception e) {
            JOptionPane.showMessageDialog(null, e);
        }
    }
}


就是说

error: non-static variable this cannot be referenced from a static context
        is = this.getClass().getClassLoader().getResourceAsStream("samp.wav");


如果我将InputStream变量设为静态,那么它会告诉我表达式的非法开头。我还删除了this关键字。问题仍然没有解决。如何解决?

最佳答案

只是避免出现问题,就像这样:

JavaApplication16.class.getClassLoader().getResourceAsStream("samp.wav");

07-25 23:29