import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.Optional;

public class GetMiles {
    public static void main(String args[]) {
        List<Student> studentList = new ArrayList<>();
        Student s = new Student();
        s.setFee("12000");
        studentList.add(s);
        Student s1 = new Student();
        s1.setFee("3000");
        studentList.add(s1);
        Optional<Student> optionalStudent =
    studentList.stream().min(Comparator.comparing(Student::getFee));
        if (optionalStudent.isPresent()) {
            System.out.println(optionalStudent.get().getFee());
        }
    }
static class Student {
        private String fee;
        public String getFee() {
            return this.fee;
        }
        public void setFee(String fee) {
            this.fee = fee;
        }
    }
   }


在上面的示例中,如果我们给出2000,则应返回3000,但应返回12000,而在大多数情况下,它应返回2000,但也将返回2000。

最佳答案

解析映射到列表中的int,然后获取最低费用,如下例代码所示:

Optional<Integer> optionalVal = studentList.stream().map(l ->
Integer.parseInt(l.getFee())).min(Comparator.comparingInt(k -> k));
if(optionalVal.isPresent()) {
String minFee = String.valueOf(optionalVal.get());
   Optional<Student> studentObj = studentList.stream().filter(p ->
   minFee.equals(p.getFee())).findFirst();
}

07-25 23:18