我有一棵D3可折叠树,问题是单个节点最多可以有4000片叶子。我想使其可滚动或扩展,即高度应同时适用于10个叶节点或数千个叶节点。
目前,我的身高参数是静态的,有人可以告诉我如何使其动态吗?
以下是代码:
$(function(){
var m = [20, 120, 20, 120],
w = 1280 - m[1] - m[3],
h = 80000 - m[0] - m[2],
i = 0,
root;
var tree = d3.layout.tree()
.size([h, w]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#modelPatterns").append("svg:svg")
.attr("width", w + m[1] + m[3])
.attr("height", h + m[0] + m[2])
.append("svg:g")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")");
d3.json("./static/data/type1Tree.json", function(json) {
root = json;
root.x0 = h / 2;
root.y0 = 0;
function toggleAll(d) {
if (d.children) {
d.children.forEach(toggleAll);
toggle(d);
}
}
// Initialize the display to show a few nodes.
root.children.forEach(toggleAll);
//toggle(root.children[1]);
//toggle(root.children[1].children[2]);
//toggle(root.children[9]);
//toggle(root.children[9].children[0]);
update(root);
});
最佳答案
您可以根据需要修改更新功能,例如以下代码...
function update(source) {
var duration = d3.event && d3.event.altKey ? 5000 : 500;
// compute the new height
var levelWidth = [1];
var childCount = function(level, n) {
if(n.children && n.children.length > 0) {
if(levelWidth.length <= level + 1) levelWidth.push(0);
levelWidth[level+1] += n.children.length;
n.children.forEach(function(d) {`
childCount(level + 1, d);
});
}
};
childCount(0, root);
newHeight = d3.max(levelWidth) * 60; // 20 pixels per line
tree = tree.size([newHeight, width]);
d3.select("svg").remove();//TO REMOVE THE ALREADY SVG CONTENTS AND RELOAD ON EVERY UPDATE
svg = d3.select("body").append("svg");
svg.attr("width", width + margin.right + margin.left)
.attr("height", newHeight + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 180; });
// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click);
nodeEnter.append("circle")
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", "-.75em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-2);
nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", "1.00em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.info1; })
.style("fill-opacity", 1e-2);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", 6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.selectAll("text")
.style("fill-opacity", 4);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.selectAll("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = svg.selectAll("path.link")
.data(links, function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
它将为您提供动态大小的树,并可以为树中的任意数量的节点服务。
希望这能解决您的目的。