python - 如何在pygame程序中实现此功能？

因此，我正在使用Pygame进行图块/网格寻宝游戏，而我正在努力思考一种实现此功能的方法。因此，每当用户按下空格时，它都会检查一个特定的图块（例如带有船的图块），并使用一个随机数（出于概率），它应该删除所有硬币或不执行任何操作。而且，每当您在图块上使用了空间时，就不应再次使用该图块。所以这些是我目前的问题。

import pygame, sys
import random
from pygame.locals import *

pygame.display.set_caption('My first game')

#colours
black = (0, 0, 0)
white = (255, 255, 255)
brown = (153, 76, 0)
blue  = (0, 0, 255)
grey  = (192,192,192)

#game dimensions
tilesize = 20
mapwidth = 30
mapheight = 20


coins = 0
ship = 1
water = 2
rock = 3
movesMade = 4

#dictionary for texture of the map
textures = { #the transform function scales the photo to the tile size
    ship : pygame.transform.smoothscale(pygame.image.load('ship.png'), (tilesize, tilesize)),
    water: pygame.transform.smoothscale(pygame.image.load('water.png'), (tilesize, tilesize)),
    rock: pygame.transform.smoothscale(pygame.image.load('rock.png'), (tilesize, tilesize)),
    coins: pygame.transform.smoothscale(pygame.image.load('chest.png'), (tilesize, tilesize)),
    movesMade: pygame.transform.smoothscale(pygame.image.load('player.png'), (tilesize, tilesize))
    }

inventory = {
    coins: 0,
    ship: 0,
    rock: 0,
    movesMade: 0
    }

#image that will represent player
PLAYER = pygame.transform.smoothscale(pygame.image.load('player.png'), (tilesize, tilesize))

#position of the player
playerPos = [0,0]

resources = [coins, movesMade]

#utilise list comprehension to create grid
tilemap = [[water for w in range(mapwidth)] for h in range(mapheight)]

pygame.init()

#set up display
displaysurf = pygame.display.set_mode((mapwidth*tilesize,mapheight*tilesize + 60))

invfont = pygame.font.Font('FreeSansBold.ttf', 18)

#loops through each row
for rw in range(mapheight):
    for cl in range(mapwidth):
        randomnumber = random.randint(0,15)
        if randomnumber == 0 or randomnumber == 1:
            tile = rock
        elif randomnumber == 2 or randomnumber == 3 :
            tile = ship
        else:
            tile = water
        #sets position in the grid
        tilemap[rw][cl] = tile

while True:
    #user events
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            if event.key == K_RIGHT and playerPos[0] < mapwidth - 1:
                playerPos[0] += 1
            if event.key == K_LEFT and playerPos[0] > 0:
                playerPos[0] -= 1
            if event.key == K_UP and playerPos[1] > 0:
                playerPos[1] -= 1
            if event.key == K_DOWN and playerPos[1] < mapheight -1:
                playerPos[1] += 1
            if event.key == K_SPACE:
                currentTile = tilemap[playerPos[1]][playerPos[0]]
                if currentTile == rock:
                    p = 10
                    while p > 0:
                        ran1 = random.randint(0,p)
                        if ran1 % 2 == 0:
                            inventory[coins] == inventory[coins] - inventory[coins]
                            p = p - 1
                        else:
                            p = p - 1

                elif currentTile == ship:
                    inventory[coins] += 50
                    inventory[movesMade] += 1

    #loops through each row
    for row in range(mapheight):
        #loops through each column in row
        for column in range(mapwidth):
            displaysurf.blit(textures[tilemap[row][column]], (column*tilesize,row*tilesize))

    displaysurf.blit(PLAYER,(playerPos[0]*tilesize,playerPos[1]*tilesize))

    placePosition = 10
    for item in resources:
        displaysurf.blit(textures[item],(placePosition, mapheight*tilesize + 20))
        placePosition += 30
        #text displays amount of coin
        textObj = invfont.render(str(inventory[item]), True, white, black)
        displaysurf.blit(textObj,(placePosition, mapheight*tilesize + 20))
        placePosition += 50

    #if inventory[coins] > 100:
    #    break
    pygame.display.update()

最佳答案

因此，每当用户按下空格时，它都会检查一个特定的图块（例如带有飞船的图块），并使用随机数（出于概率），它应该删除所有硬币或不执行任何操作。[...]


==是比较运算符。因此，inventory[coins] == inventory[coins] - inventory[coins]将inventory[coins]与0（inventory[coins] - inventory[coins]）进行比较，结果无处可去。

如果您已解决问题，则while循环将执行10次检查。硬币丢失的可能性非常高：

p = 10
while p > 0:
    ran1 = random.randint(0,p)
    if ran1 % 2 == 0:
        inventory[coins] = inventory[coins] - inventory[coins]
        p = p - 1
    else:
        p = p - 1

定义一个百分比（percent）值，该值定义硬币没有丢失，并检查随机值是否超出限制：

percent = 30 # coins are kept with a probability of 30 percent and will be lost by 70 percent
ran1 = random.randint(0,100) # random value in [0, 99]
    if ran1 >= percent:
    inventory[coins] = 0

  [...]每当您在图块上使用了空间时，就不应再次使用该图块。


创建一个字典，存储有关“用途”磁贴的信息：

visit = {}

如果按下空格，则将磁贴标记为“二手”：

pos = (playerPos[1], playerPos[0])
visit[pos] = True

检查以下位置之前是否已经“使用”了图块：

pos = (playerPos[1], playerPos[0])
if not pos in visit:
    # [...]

顺便说一下，使用pygame.Surface.fill()清除每帧开始处的显示。

displaysurf.fill(black) # choose background color

主循环代码清单：

visit = {}
while True:

    displaysurf.fill(black) # choose background color

    #user events
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            if event.key == K_RIGHT and playerPos[0] < mapwidth - 1:
                playerPos[0] += 1
            if event.key == K_LEFT and playerPos[0] > 0:
                playerPos[0] -= 1
            if event.key == K_UP and playerPos[1] > 0:
                playerPos[1] -= 1
            if event.key == K_DOWN and playerPos[1] < mapheight -1:
                playerPos[1] += 1
            if event.key == K_SPACE:
                pos = (playerPos[1], playerPos[0])
                if not pos in visit:
                    visit[pos] = True
                    currentTile = tilemap[playerPos[1]][playerPos[0]]
                    if currentTile == rock:
                        percent = 30 # coins are kept with a probability of 30 percent and will be lost by 70 percent
                        ran1 = random.randint(0,100) # random value in [0, 99]
                        if ran1 >= percent:
                            inventory[coins] = 0

                    elif currentTile == ship:
                        inventory[coins] += 50
                        inventory[movesMade] += 1
    # [...]

关于python - 如何在pygame程序中实现此功能？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/54427344/