这是一个最小的复制:
extern crate csv;
use std::fs::File;
use std::io::Write;
fn do_write(writer: &mut csv::Writer<File>, buf: &[u8]) {
// The error is coming from this line
writer.write_record(buf);
}
fn main() {
let mut writer = csv::Writer::from_path(r"c:\temp\file.csv").unwrap();
let str = "Hello, World!".to_string();
do_write(&mut writer, str.as_bytes());
}
导致编译错误:
error[E0277]: the trait bound `u8: std::convert::AsRef<[u8]>` is not satisfied
--> src/main.rs:7:16
|
7 | writer.write_record(buf);
| ^^^^^^^^^^^^ the trait `std::convert::AsRef<[u8]>` is not implemented for `u8`
|
= note: required because of the requirements on the impl of `std::convert::AsRef<[u8]>` for `&u8`
这个错误是什么意思?看来我已经通过了
u8
切片? 最佳答案
查看write_record
的签名:
fn write_record<I, T>(&mut self, record: I) -> Result<()>
where
I: IntoIterator<Item = T>,
T: AsRef<[u8]>,
它期望可以成为值的迭代器的东西。您提供的是
&[u8]
,它是一个迭代器,但仅包含&u8
值。错误是这些&u8
没有实现AsRef<[u8]>
。您可以将单个传入的字符串包装在另一个数组中,以创建可以充当迭代器的对象:
writer.write_record(&[buf]);
关于csv - 尝试写入CSV记录时出现错误 “the trait ` std::convert::AsRef <[u8] >` is not implemented for ` u 8`”,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47016911/