我使用Backbone-Relational创建一个复杂的模型层次结构,代码如下所示:
var ModelA = Backbone.Model.extend({
initialize: function () {
console.log('model a initialized!')
}
});
var CollectionA = Backbone.Collection.extend({
model: ModelA
});
var ModelB = Backbone.RelationalModel.extend({
relations: [{
type: Backbone.HasMany,
key: 'Collection',
collectionType: CollectionA
}]
});
var data = new ModelB({
name: 'ModelB',
Collection: [{
name: 'ModelA-1'
}, {
name: 'ModelA-2'
}]
});
console.log(data.get('Collection').at(0) instanceof ModelA); // false
console.log(data.get('Collection').at(0) instanceof ModelB); // true
console.log(JSON.stringify(data.toJSON()));
// {"name":"ModelB","Collection":[{"name":"ModelA-1","Collection":[]},{"name":"ModelA-2","Collection":[]}]}
如您所见,即使成功创建了
ModelB
,也不会调用initialize()
中的ModelA
。检查类型可证明集合内的对象不是ModelA
。我怎样才能解决这个问题? 最佳答案
必须进行两项更改:将ModelA
设置为RelationalModel
(而不仅仅是标准的),并告诉ModelB
ModelA
是其relatedModel
,如下所示:
var ModelA = Backbone.RelationalModel.extend({
initialize: function () {
console.log('model a initialized!')
}
});
...
var ModelB = Backbone.RelationalModel.extend({
relations: [{
type: Backbone.HasMany,
relatedModel: 'ModelA',
key: 'Collection',
collectionType: CollectionA
}]
});
Demo。
关于javascript - 如何处理嵌套在RelationalModel中的集合?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/27627504/