android - 不要在onRestoreInstanceState上运行函数

我正在开发一个应用程序，当您转到屏幕时，可以从在onCreate中创建的对话框中选择位置。选择位置后，它将把它写入预先定义的TextView中。我遇到的一个问题是，当屏幕方向更改时，它会重新创建对话框，而我试图使其不触发对话框功能。

这是我在类文件中拥有的基本知识。

  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.emergpolice);

    form_location = (TextView) findViewById(R.id.input_location);

    if(form_location == null || form_location.getText().equals("")){
        setLocation();
    }
}

@Override
protected void onSaveInstanceState(Bundle outState){
    super.onSaveInstanceState(outState);
    outState.putString("LOCATION", (String)form_location.getText());
}

@Override
protected void onRestoreInstanceState(Bundle savedInstanceState){
    super.onRestoreInstanceState(savedInstanceState);
    form_location.setText(savedInstanceState.getString("LOCATION"));
}

public void setLocation(){
    db = new DatabaseHandler(this);
    db.open();
    final CharSequence[] locOpt = {getString(R.string.dialog_items_current_location),getString(R.string.dialog_items_home),getString(R.string.dialog_items_enter_manually)};
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle(getString(R.string.header_choose_location));
    builder.setSingleChoiceItems(locOpt, -1, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int item){
            if(locOpt[item].equals(getString(R.string.dialog_items_home))){
                Cursor cur = db.userInfo();
                String address = cur.getString(cur.getColumnIndex("address"));
                String city = cur.getString(7);
                String county = cur.getString(8);
                String state = cur.getString(9);
                String zip = cur.getString(10);
                db.close();
                form_location.setText(address + ", " + city + ", " + county + ", " + state + ", " + zip);
            }
            if(locOpt[item].equals(getString(R.string.dialog_items_current_location))){
                Toast.makeText(getApplicationContext(), locOpt[item], Toast.LENGTH_SHORT).show();
            }
            dialog.cancel();
        }
    });
    AlertDialog alert = builder.create();
    alert.show();
}

我布局中的TextView是

        <TextView
            android:id="@+id/input_location"
            android:layout_width="wrap_content"
            android:layout_below="@+id/text_location"
            android:layout_height="wrap_content"
            android:text="" />

就触发setLocation()而言，已经尝试了几种方案来检查字符串长度（是否为null）。当屏幕更改时，它会显示原始选择的位置，但仍会触发对话框。

最佳答案

您总是调用方法setLocation，因为每次调用onCreate的Activity方法都会是form_location.getText().equals("")（因为重新创建了true（而且很可能不会在其上设置文本）它在布局文件中））。

为避免这种情况，请使用TextView方法的savedInstanceState：

if (savedInstanceState == null){
   // if savedInstanceState is null the activity is created for the first time
   setLocation();
} else {
   // if not null then the activity is recreated so restore the TextView text
   form_location.setText(savedInstanceState.getString("LOCATION"));
}

关于android - 不要在onRestoreInstanceState上运行函数，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/10760904/