Joiner
的初始化在这里不正确吗?我有以下课程,当我尝试将示例paths
数组与joiner
结合在一起时,我得到了NullPointerException
。
public class CPath {
private static final Joiner joiner = Joiner.on("/");
private String[] elements;
@Override
public String toString() {
return joiner.join(elements);
}
}
// main method
final String[] paths = {"a/b/c", "d", "", null, "e/f/g", "h/i", null, ""};
final CPath c3 = new CPath(paths);
c3.toString(); //<<<< NPE
最佳答案
您必须使用skipNulls()
或useForNull(defaultValue)
,它位于其文档的顶部;
如果未指定skipNulls()和useForNull(String),则任何给定元素为null时,联接方法都将引发NullPointerException。
因此,您必须像这样初始化joiner
;
Joiner joiner = Joiner.on("/").skipNulls();
要么
Joiner joiner = Joiner.on("/").useForNull("");
Documentation of Joiner from Guava