如何比较两个可调用类型以检查它们是否相等或相同?
function addCallable(callable $cb)
{
if(/*already exists*/)
throw new Exception("Callable was already added to the collection");
else
$this->collection[] = $cb;
}
function removeCallable(callable $cb)
{
$key = array_search(/* ??? */);
unset($this->collection[$key]);
}
$this->addCallable(array('MyClass', 'myCallbackMethod'));
try{ $this->addCallable('MyClass::myCallbackMethod'); }catch(Exception $e){}
$this->removeCallable('MyClass::myCallbackMethod');
非常感谢你
最佳答案
您可以使用 is_callable 函数的第三个参数 来获取 可调用名称 ,它是一个字符串。
如果可调用对象是 array('MyClass', 'myCallbackMethod')
,则可调用对象名称将为 'MyClass::myCallbackMethod'
。
function addCallable(callable $cb)
{
is_callable($cb, true, $callable_name);
if(isset($this->collection[$callable_name])) {
throw new Exception("Callable was already added to the collection");
} else {
$this->collection[$callable_name] = $cb;
}
}
function removeCallable(callable $cb)
{
is_callable($cb, true, $callable_name);
unset($this->collection[$callable_nam]);
}
关于php - 如何比较php可调用类型?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/24034206/