c# - 如何使用Infopath向WCF Web服务提交表单

我有一个小型的Intranet服务，需要工作，我们正在将测试配置从一个域提交到另一个域，没有将建立的域信任，并且由于输入模板会大量更改数据，因此我们决定将Infopath用于脚本编写者/实验室的测试人员输入他们的数据。我想，亲爱的，也许我应该做一个小型WCF服务器并将其托管在我们的IIS服务器上……应该很容易，对吧？

排队笑

我已经使用从Infopath到bool TestInfoPathSubmit(string testString);的OperationContract的简单字符串提交测试了连接性。它在开发服务器和生产服务器上都可以正常工作，减去了似乎总是发生的少量权限高峰。

我已经从使用工作的xml并使用.NET ResultDataSet.xsd应用程序生成的xsd.exe文件中使用了很多东西，所以我知道它是有效的，因此我可以跳过链接该代码。但是这里是其余的：

界面/合同

[DataContractFormat(Style = OperationFormatStyle.Document)]
[ServiceContract]
public interface IService
{

    [XmlSerializerFormat]
    [OperationContract]
    bool ResultFromInfopath(XmlDocument xdoc);
}

注意：已注意到[XmlSerializerFormat]可以避免XmlDocument无法在WCF中进行序列化/反序列化的问题。

服务

public class Service1 : IService
{
    public bool ResultFromInfopath(XmlDocument xdoc)
    {
        try
        {
            var xreader = new XmlNodeReader(xdoc);
            var dataset = new ResultDataSet();
            dataset.ReadXml(xreader);
            Debug.Print("XML has been read in and ready to process");

            return true;
        }
        catch (Exception ex)
        {
            Debug.Print(ex.Message);
            return false;
        }
    }
}

网络配置

<?xml version="1.0"?>
<configuration>

  <appSettings>
    <add key="aspnet:UseTaskFriendlySynchronizationContext" value="true" />
  </appSettings>
  <system.web>
    <compilation debug="true" targetFramework="4.5" />
    <httpRuntime targetFramework="4.5"/>
  </system.web>
  <system.serviceModel>
    <behaviors>
      <serviceBehaviors>
        <behavior>
          <serviceMetadata httpGetEnabled="true" httpsGetEnabled="true"/>
          <serviceDebug includeExceptionDetailInFaults="true"/>
        </behavior>
      </serviceBehaviors>
    </behaviors>
    <protocolMapping>
        <add binding="basicHttpBinding" scheme="http" />
    </protocolMapping>
    <serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true" />
  </system.serviceModel>
  <system.webServer>
    <modules runAllManagedModulesForAllRequests="true"/>
    <directoryBrowse enabled="true"/>
  </system.webServer>

</configuration>

没什么幻想，试图保持简单。我使用xsd文件创建了Infopath文档模板，并将Submit链接到Web Service，然后选择了作为完整XmlDocument提交的选项，包括处理说明。这是我犯错的地方。不要包括处理说明。 MSDN - XmlDictionaryReader是消息流的默认解码器，它不接受InfoPath放入XmlDocument中嵌入的处理指令。

您返回的错误是提交无法完成：

InfoPath cannot submit the form.
An error occurred while the form was being submitted.
The SOAP response indicates that an error occurred:

Error in deserializing body of request message for operation 'ResultFromInfopath'.
<detail>
    <ExceptionDetail xmlns="http://schemas.datacontract.org/2004/07/System.ServiceModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
        <HelpLink i:nil="true"/>
        <InnerException>
            <HelpLink i:nil="true"/>
            <InnerException>
                <HelpLink i:nil="true"/>
                <InnerException i:nil="true"/>
                <Message>
                    Processing instructions (other than the XML declaration) and DTDs are not supported. Line 1, position 485.
                </Message>
                <StackTrace>
                    at System.Xml.XmlExceptionHelper.ThrowXmlException(XmlDictionaryReader reader, String res, String arg1, String arg2, String arg3)
                    at System.Xml.XmlUTF8TextReader.ReadDeclaration()
                    at System.Xml.XmlUTF8TextReader.Read()
                    at System.Xml.XmlLoader.LoadNode(Boolean skipOverWhitespace)
                    at System.Xml.XmlLoader.ReadCurrentNode(XmlDocument doc, XmlReader reader)
                    at System.Xml.XmlDocument.ReadNode(XmlReader reader)
                    at System.Xml.Serialization.XmlSerializationReader.ReadXmlNode(Boolean wrapped)
                    at System.Xml.Serialization.XmlSerializationReader.ReadXmlDocument(Boolean wrapped)
                    at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderIService.Read2_ResultFromInfopath()
                    at Microsoft.Xml.Serialization.GeneratedAssembly.ArrayOfObjectSerializer1.Deserialize(XmlSerializationReader reader)
                    at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events)
                </StackTrace>
                <Type>
                    System.Xml.XmlException
                </Type>
            </InnerException>
            <Message>
                There is an error in XML document (1, 485).
            </Message>
            <StackTrace>
                at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events)
                at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle)
                at System.ServiceModel.Dispatcher.XmlSerializerOperationFormatter.DeserializeBody(XmlDictionaryReader reader, MessageVersion version, XmlSerializer serializer, MessagePartDescription returnPart, MessagePartDescriptionCollection bodyParts, Object[] parameters, Boolean isRequest)
            </StackTrace>
            <Type>
                System.InvalidOperationException
            </Type>
        </InnerException>
        <Message>
            Error in deserializing body of request message for operation 'ResultFromInfopath'.
        </Message>
        <StackTrace>
            at System.ServiceModel.Dispatcher.XmlSerializerOperationFormatter.DeserializeBody(XmlDictionaryReader reader, MessageVersion version, XmlSerializer serializer, MessagePartDescription returnPart, MessagePartDescriptionCollection bodyParts, Object[] parameters, Boolean isRequest)
            at System.ServiceModel.Dispatcher.XmlSerializerOperationFormatter.DeserializeBody(XmlDictionaryReader reader, MessageVersion version, String action, MessageDescription messageDescription, Object[] parameters, Boolean isRequest)
            at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeBodyContents(Message message, Object[] parameters, Boolean isRequest)
            at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeRequest(Message message, Object[] parameters)
            at System.ServiceModel.Dispatcher.DispatchOperationRuntime.DeserializeInputs(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.DispatchOperationRuntime.InvokeBegin(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage5(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage41(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage4(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage31(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage3(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage2(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage11(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage1(MessageRpc&amp; rpc)
            at System.ServiceModel.Dispatcher.MessageRpc.Process(Boolean isOperationContextSet)
        </StackTrace>
        <Type>
            System.ServiceModel.CommunicationException
        </Type>
    </ExceptionDetail>
</detail>

下面提供了答案。

最佳答案

由于XmlDictionaryReader无法从Infopath读取指令，因此您需要将Infopath的数据提交设置为“为所选参数提交以下数据：”->“字段或组”。从XSD中选择基础节点作为Infopath的元素，然后让数据连接向导完成其余的工作。

将要提交的XmlDocument xdoc必须读入数据集，此时，您可以很好地使用数据。

关于c# - 如何使用Infopath向WCF Web服务提交表单，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/20648152/