java - 罗马数字转换器与众不同

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我不断收到此错误代码：

---- jGRASP执行：javac -g RomanNumerals.java

RomanNumerals.java:56：无法访问的语句

充实：

1个错误

---- jGRASP楔形：进程的退出代码为1。
 ---- jGRASP：操作完成。

到目前为止，这是我的代码：

import java.util.Scanner;

public class RomanNumerals
{
   public static void main(String[] args)
   {
      int input;

      Scanner keyboard = new Scanner(System.in);

      System.out.print("Enter a number: ");
      input = keyboard.nextInt();

      switch (input)
      {
         case 1:
            System.out.println("I");
            break;
         case 2:
            System.out.println("II");
            break;
         case 3:
            System.out.println("III");
            break;
         case 4:
            System.out.println("IV");
            break;
         case 5:
            System.out.println("V");
            break;
         case 6:
            System.out.println("VI");
            break;
         case 7:
            System.out.println("VII");
            break;
         case 8:
            System.out.println("VIII");
            break;
         case 9:
            System.out.println("IX");
            break;
         case 10:
            System.out.println("X");
            break;
         defult:
            System.out.println("Please enter a number between 1 and 10. ");
     }
   }
}

最佳答案

您输入了“默认值：”，但应为“默认值：”
尝试

default:
            System.out.println("Please enter a number between 1 and 10. ");