当我尝试用一个任务编译线程池时,出现以下错误:
错误:'无效ThreadPool :: enqueue(F)[与F =
CConnection :: handle()::]',使用本地类型声明
'CConnection :: handle()::',已使用但从未定义
[-放任]
这是线程池声明:
class ThreadPool {
public:
ThreadPool(size_t);
template<class F>
void enqueue(F f);
~ThreadPool();
private:
// need to keep track of threads so we can join them
std::vector< std::unique_ptr<boost::thread> > workers;
// the io_service we are wrapping
boost::asio::io_service service;
boost::asio::io_service::work working;
friend class Worker;
};
这是函数,要使用线程池进行测试的函数:
void CConnection::handle()
{
ThreadPool pool(4);
pool.enqueue([1]
{
std::cout << "hello " << 1 << std::endl;
boost::this_thread::sleep(
boost::posix_time::milliseconds(1000)
);
std::cout << "world " << 1 << std::endl;
});
char * databuffer;
databuffer = new char[16];
for(int i = 0;i<16;i++)
{
databuffer[i] = 0x00;
}
databuffer[0] = 16;
databuffer[4] = 1;
databuffer[8] = 1;
databuffer[12] = 1;
asynchronousSend(databuffer, 16);
}
这是入队定义:
template<class F>
void ThreadPool::enqueue(F f)
{
service.post(f);
}
有人可以发现我做错了吗?
最佳答案
enqueue的定义是否在ThreadPool.h标头中?这是模板方法所必需的
关于c++ - 线程池编译错误,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16877034/