如何根据ate
键的值将这个散列数组一分为二?
array = [
{ name: "Gad", ate: true },
{ name: "Lad", ate: false },
{ name: "Bad", ate: true },
{ name: "Sad", ate: false }
]
示例输出
array_1 = [
{ name: "Gad", ate: true },
{ name: "Bad", ate: true }
]
array_2 = [
{ name: "Lad", ate: false },
{ name: "Sad", ate: false }
]
最佳答案
使用Enumerable#partition
方法:
array.partition { |x| x[:ate] }
# => [[{:name=>"Gad", :ate=>true}, {:name=>"Bad", :ate=>true}],
# [{:name=>"Lad", :ate=>false}, {:name=>"Sad", :ate=>false}]]
或:
array_1, array_2 = array.partition { |x| x[:ate] }
array_1
# => [{:name=>"Gad", :ate=>true}, {:name=>"Bad", :ate=>true}]
array_2
# => [{:name=>"Lad", :ate=>false}, {:name=>"Sad", :ate=>false}]